Answer:
26y
Step-by-step explanation:
26y and 52y.
13*2*y and 13*2*2 *y
Common is 13*2*y
or 26y
Hope this helps!
Given:
Consider the equation is:

To prove:
by using the properties of logarithms.
Solution:
We have,

Taking left hand side (LHS), we get

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

![[\because \log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%5En%3Dn%5Clog%20x%5D)

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

Hence proved.
Using a system of equations, it is found that since 20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
- Variable c: number of child bikes.
- Variable a: number of adult bikes.
Each child bike requires 4 hours to build, as do each adult bike. The company has 100 hours of testing, hence:
4c + 4a = 100.
c + a = 25.
With 20 child bikes and 6 adult bikes in a week, we have that c = 20, a = 26, hence:
c + a = 26
20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.
More can be learned about a system of equations at brainly.com/question/24342899
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