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3 years ago

What will occur when two have reach one another

1 answer:

5 0

Well, you would have to be more specific! Sorry I couldn't help you, but if you have the whole question and it is udnerstandable, please repost your question!

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The slope of a line on a distance-time graph represents _____. distance time displacement speed

lisabon 2012 [21]

Answer:

speed

Explanation:

The slope of a line on any distance-time graph represents the speed of the object.

Velocity only comes in when there is speed of the object in a particular direction.

4 0

3 years ago

One point of the circuit is grounded (V = 0). What are the (a) size and (b) direction (up or down) of the current through resist

Svetach [21]

<h3>Answer:</h3>

(a) i₁ = 0.03818 A = 38.18 mA

(b) downward

(c) i₂ = 0.01091 A = 10.91 mA

(d) rightward

(e) i₃ = 0.02727 A = 27.27 mA

(f) leftward

(g) Eₐ = 3.818 Volts

<h3>Question:</h3>

The complete question is stated below and the figure is provided in the attachment:

In Fig. 27-47, E 1 = 6.00 V, E 2 = 12.0 V, R1 = 100 Ω,

R2 = 200 Ω, and R3 = 300 Ω. One point of the circuit is grounded

(V = 0). What are the (a) size and (b) direction (up or down) of the

current through resistance 1, the (c) size and (d) direction

(left or right) of the current through resistance 2, and the

(e) size and (f) direction of the current through resistance 3?

(g) What is the electric potential at point A?

<h3></h3><h3>Explanation:</h3>

Applying Kirchoff's voltage law in the loops of botg E₁ and E₂, in the clockwise and anti clockwise direction:

E₁ - i₂R₂ - i₁R₁ = 0

E₂ - i₃R₃ - i₁R₁ = 0

If, we apply Kirchhoff's current law at junction A, we get:

i₁ = i₂ + i₃

Using these relations in loop equations, and re-arranging:

E₁ - i₂R₂ - (i₂ + i₃) R₁ = 0 ___________ eqn (1)

E₂ - i₃R₃ - (i₂ + i₃) R₁ = 0 ___________ eqn (2)

Eqn (1) implies:

6 - 200 i₂ - 100 i₂ - 100 i₃ = 0

i₂ = (6 - 100i₃)/300

Eqn (2) implies:

12 - 300 i₃ - 100 i₂ - 100 i₃ = 0

12 - 400 i₃ = 100 i₂

using value of i₃ from eqn (1)

12 - 400 i₃ = (1/3)(6 - 100 i₃)

36 - 1200 i₃ = 6 - 100 i₃

1100 i₃ = 30

i₃ = 0.02727 A

using this value in eqn of i₂:

i₂ = [6 - 100(0.02727)]/300

i₂ = (6 - 2.727)/300

i₂ = 0.01091 A

Since:

i₁ = i₂ + i₃

i₁ = 0.01091 A + 0.02727 A

i₁ = 0.03818 A

(a)

i₁ = 0.03818 A = 38.18 mA

(b)

Since, the value of current is positive, thus it will have the direction that was assumed.

Therefore, its direction will downward

(c)

i₂ = 0.01091 A = 10.91 mA

(d)

Since, the value of current is positive, thus it will have the direction that was assumed.

Therefore, its direction will rightward

(e)

i₃ = 0.02727 A = 27.27 mA

(f)

Since, the value of current is positive, thus it will have the direction that was assumed.

Therefore, its direction will leftward

(g)

With respect to the grounded portion, the potential drop at the resistance 1 will be equal to the potential at A Eₐ.

Therefore,

Eₐ = i₁R₁

Eₐ = (0.03818 A)(100 Ω)

Eₐ = 3.818 Volts

3 0

4 years ago

I need help with one through six please

dybincka [34]

Answer:

1] 8500000 = 8.5 × 10⁶

2] .000072 = 7.2 × 10⁻⁵

3] 5.3 × 10⁴ = 53000

4] 2.8 × 10⁻³ = 0.0028

5] Velocity = $\frac{distance}{time}$

V = $\frac{50}{10}$

V = 5 m/s

6] Acceleration = $\frac{V1-V2}{time}$

A = $\frac{30-15}{3}$

A = $\frac{15}{3}$

A = 3 m/s²

7 0

2 years ago

suppose larry stands with more weight on one scale than the other if one scale reads 400 N. what does the other read?

Evgen [1.6K]

The other scale will either have a higher or lower number because 400 could be the bigger number or the smaller number but we don't know that so you cant exactly answer it.

8 0

3 years ago

Read 2 more answers

Caroline, a piano tuner, suspects that a piano's B4 key is out of tune. Normally, she would play the key along with her B4 tunin

Sergeeva-Olga [200]

Answer:

455.9 Hz, Flat

Explanation:

The beat frequency is basically the difference between the frequency of the B4 note and the frequency of the A4 tuning fork. This means the B4 note is 15.9 Hz off of 440Hz, and 67.4 Hz off of 525.3 Hz. As B4 is between the two notes, it would make sense to find its frequency by adding 15.9 to 440 and subtracting 67.4 from 523.3, both if which give us a frequency 455.9 Hz for the B4 key. This is because the note doesn't change for the different turning forks so both differences should result in the same frequency. Because the note should be 493.9 frequency but instead has a frequency of 455.9 Hz, it is flat because the frequency is lower than it is supposed to be.

Hope this helped!

7 0

4 years ago