The electrical energy consumed in one year by using the light bulbs is 8,760 kWh.
The given parameters:
- Number of light bulbs = 10
- Power consumed by each bulb = 100 W
- Time of energy consumption, t = 1 year
<h3>What is electrical energy?</h3>
This is the electric power consumed or dissipated at a given period of time.
The electrical energy consumed in one year by using the light bulbs is calculated as
E = Pt
Thus, the electrical energy consumed in one year by using the light bulbs is 8,760 kWh.
Learn more about electrical energy here: brainly.com/question/60890
The final velocity of the block A will be 2.5 m/sec. The principal of the momentum conversation is used in the given problem.
<h3>What is the law of conservation of momentum?</h3>
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and m₂ will be u₁=5 and u₂=0 m/s respectively,
According to the law of conservation of momentum
Momentum before collision =Momentum after collision
m₁u₁+m₂u₂=(m₁+m₂)v
M×5+3M×0=[M+3M]v
The final velocity is found as;
V=51.25 m/s
The velocity of block A is found as;
Hence, the final velocity of the block A will be 2.5 m/sec.
To learn more about the law of conservation of momentum, refer;
brainly.com/question/1113396
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Answer: y(t)= 1/π^2 sin(6*π^2*t)
Explanation: In order to solve this problem we have to consider the general expression for a harmonic movement given by:
y(t)= A*sin (ω*t +φo) where ω is the angular frequency. A is the amplitude.
The data are: ν= 3π; y(t=0)=0 and y'(0)=6.
Firstly we know that 2πν=ω then ω=6*π^2
Then, we have y(0)=0=A*sin (6*π^2*0+φo)= A sin (φo)=0 then φo=0
Besides y'(t)=6*π^2*A*cos (6*π^2*t)
y'(0)=6=6*π^2*A*cos (6*π^2*0)
6=6*π^2*A then A= 1/π^2
Finally the equation is:
y(t)= 1/π^2 sin(6*π^2*t)
Answer:
8.33 m/s, 36.87° North of East
Explanation:
= Mass of car = 1000 kg
= Velocity of car = 15 m/s
= Mass of truck = 2000 kg
= Velocity of truck = 10 m/s
M = Combined mass = 1000+2000 = 3000 kg
Momentum
Momentum of car traveling East is 15000 kgm/s
Momentum of truck traveling North is 20000 kgm/s
Angle
As the two vehicles are vectors, the resultant velocity is
Velocity of the two vehicles when they are locked together is 8.33 m/s and direction is 36.87° North of East
Complete question is The frequency of the fundamental of the guitar string is 320 Hz. At what speed c do waves move along that string? wavelength is 40 cm.
Answer:
128 m/s
Explanation:
In case where fundamental frequency is given, the speed with waves travel along the string can be calculated using the following formula:
v = f (2L) where L is the length of the string (L = λ/2)
⇒v= f λ
f = 320 Hz (given)
λ = 40 cm = 0.40 m
Substitute the values:
⇒ v = 320 Hz × 0.40 m= 128 m/s
