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3 years ago

Please help me I’ll mark you Brainly!! QUICK

Physics

2 answers:

babunello [35]3 years ago

7 0

I think it is option (C)

If the answer was helpful then mark me as brainly.

jarptica [38.1K]3 years ago

3 0

Answer:

Explanation:

The motion of the wheelbarrow is going straight, so the wheelbarrow accelerates faster. Since it doesn't say about moving the motion onto its side, it's A.

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A ball is swung in a horizontal circle at a constant speed. Each circle takes 0.85 seconds to complete and the rope is 0.40 m lo

BaLLatris [955]

Answer:

The centripetal acceleration will be "21.785 m/s²".

Explanation:

The given values are:

Time,

t = 0.85 seconds

Length of rope,

r = 0.40 m

Mass of ball,

m = 0.80 kg

As we know,

⇒ $w=\frac{2 \pi}{t}$

On substituting the values, we get

⇒ $=\frac{2\times 3.14}{0.85}$

⇒ $= \frac{6.28}{0.85}$

⇒ $=7.38 \ rad/s^2$

The centripetal acceleration will be:

⇒ $a=r\times w^2$

⇒ $=0.40\times (7.38)^2$

⇒ $=0.40\times 54.46$

⇒ $=21.785 \ m/s^2$

7 0

3 years ago

What are the horizontal and vertical components of a lizard’s displacement if it has climbed 7m directly up a tree?

madam [21]

Answer:

The horizontal component is zero.

The vertical component is $7\sin\theta$

Explanation:

Given that,

The lizard climb 7m directly up on a tree.

We know that,

The horizontal component is

$x=\cos\theta$

The vertical component is

$y=\sin\theta$

If the lizard climb 7m directly up on a tree then,

We need to find the components

Using given data

The horizontal component of lizard is

$x=0$

The vertical component is

$y=7\sin\theta$

Hence, The horizontal component is zero.

The vertical component is $7\sin\theta$

7 0

3 years ago

Momentum is a vector quantity that depends

MissTica

On the change in potential energy

3 0

3 years ago

Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c

stira [4]

Answer:

i) 24.5 m/s

ii) 30,656 m

iii) 89,344 m

Explanation:

Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer

i) Los parámetros dados son;

Altura inicial, s = 120 m

El tiempo en caída libre = 2.5 s

De la ecuación de caída libre, tenemos;

v = u + gt

Dónde:

u = Velocidad inicial = 0 m / s

g = Aceleración debida a la gravedad = 9.81 m / s²

t = Tiempo de caída libre = 2.5 s

Por lo tanto;

v = 0 + 9.8 × 2.5 = 24.5 m / s

ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación

s = u · t + 1/2 · g · t²

= 0 × 2.5 + 1/2 × 9.81 × 2.5² = 30.656 m

iii) La altura restante = 120 - 30.656 = 89.344 m.

6 0

3 years ago

What is the force of gravity between you and a standard tennis ball if you are 1 meter away

faltersainse [42]

Answer:

WHY MUST I CRYYYYYYYY

Explanation:

3 0

3 years ago