Which statements describe what is occurring at t=5 seconds? Check all that apply

GREYUIT [131]

To keep noise from entering your space, look for sound blockers

8 0

3 years ago

With the same block-spring system from above, imagine doubling the displacement of the block to start the motion. By what factor

Fofino [41]

Answer:

A) K / K₀ = 4 b) v / v₀ = 4

Explanation:

A) For this exercise we can use the conservation of mechanical energy

in the problem it indicates that the displacement was doubled (x = 2xo)

starting point. At the position of maximum displacement

Em₀ = Ke = ½ k (2x₀)²

final point. In the equilibrium position

$Em_{f}$ = K = ½ m v²

Em₀ = Em_{f}

½ k 4 x₀² = K

(½ K x₀²) = K₀

K = 4 K₀

K / K₀ = 4

B) the speed value

½ k 4 x₀² = ½ m v²

v = 4 (k / m) x₀

if we call

v₀ = k / m x₀

v = 4 v₀

v / v₀ = 4

3 0

3 years ago

A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i

nydimaria [60]

1. -23.2 J

The gravitational potential energy of the ball is given by

$U=mgh$

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J$

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

$U=mgh$

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

$U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J$

3. 0 J

As before, the gravitational potential energy of the ball is given by

$U=mgh$

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J$

4 0

4 years ago

A 350-g baseball is shot out of a small cannon with a velocity of 9.0 m/s. The baseball flies horizontally at a constant height

stira [4]

Answer:

$9.5 kg m^2/s$

Explanation:

The angular momentum of an object is given by:

$L=mvr$

where

m is the mass of the object

v is its velocity

r is the distance of the object from axis of rotation

Here we have:

m = 350 g = 0.35 kg is the mass of the ball

v = 9.0 m/s is the velocity

r = 3.0 m is the distance of the object from axis of rotation (if we take the ground as the centre of rotation)

Therefore, the angular momentum is:

$L=(0.35)(9.0)(3.0)=9.5 kg m^2/s$

4 0

3 years ago

Which of the following is a possible use for nuclear energy?

belka [17]

Nuclear energy can be used to power all of the above choices. Nuclear power plants produce radioactive waste that must be stored properly. It is very impossible for a nuclear power plant to have no waste at all since lots of chemicals are used to create the process as it gives energy to other machines, weapons such as bombs and powering submarines. Radioactive waste can not be released into local water supplies since the wastes are very radioactive and may cause mutation to the fishes and bioaccumulation which will affect humans as well. It will also cause air pollution if the chemicals are not stored properly.

5 0

3 years ago

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