Answer:
a) 1.855m/s^2, 9.71\° to the east-north
b) 0.103N, 9.46° to the west-south
Explanation:
To find the acceleration of the system you can assume that the forces are applied in a xy plane, where force toward north are directed in the +y direction, and forces to the east in the +x direction. BY taking into account the components of the acceleration for each axis you obtain the following systems of equations:

m: mass of the crumb of bread = 0.056kg
you simplify the equations an replace the values of the mass in order to obtain the acceleration components:


then, the acceleration of the system has a magnitude of 1.855m/s^2 and a direction of 9.71\° to the east-north
The fifth force must cancel both x an y components of the previous net force, that is:


the, the force needed to reach the equilibrium has a magnitude of 0.103N and a direction of 9.46° to the west-south
The answer is do not break, the key avoiding skids is to always smoothly apply your brakes and accelerator and to turn slowly and smoothly. Reducing of the speed before oncoming turns and once driving in possibly hazardous circumstances such as wet, icy or snow covered roadways or on roadways with loose gravel.
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Hope this helps!
The solution to the problem is as follows:
Normal force is m*g plus 240 N*sin30.
<span>30 kg*9.8 m/s^2 + 240 N*sin30 = 414 N
</span>
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Answer:
0.57 m
Explanation:
First of all, we need to calculate the time it takes for the ball to cover the horizontal distance between the starting position and the crossbar. This can be done by analzying the horizontal motion only. In fact, the horizontal velocity is constant and it is

And the distance to cover is
d = 19 m
So the time taken is

Now we want to find how high the ball is at that time. The initial vertical velocity is

So the vertical position of the ball at time t is

where g = 9.8 m/s^2 is the acceleration of gravity. Substituting t = 2.04 s, we find

The crossbar height is 3.05 m, so the difference is

So the ball passes 0.57 m above the crossbar.