All categories

3 years ago

What happens to pressure as volume increases

2 answers:

7 0

Answer: So if the volume increases, the pressure decreases. ... Boyle's law states that for a fixed amount of gas in an enclosed system at constant temperature, pressure and volume are inversely proportional

Explanation:

This linear relationship between pressure and volume means doubling the volume of a given mass of gas decreases its pressure by half.

PV = c

P ∝ 1/V

Colt1911 [192]3 years ago

4 0

If the volume increases then the pressure would decrease.

You might be interested in

What is the mass of 2.5 moles of Na2O?<br> its a little 2 on the equation

Rzqust [24]

I'll be using dimensional analysis to help out.

2.5mol Na2O * ( X gNa2O / 1 molNa2O) = ? gNa2O

X gNa2O is the molar mass of the molecule. To find that we must add up the molar masses of all of the elements in the molecule.

There are 2 Na (Sodium).
And 1 O (Oxygen).

The Molar Mass of Na = 2 * 22.99 g/mol (It's multiplied by 2 because there are 2 of them in the molecule)

The Molar mass of O = 16.00 g/mol

If you are confused on where I found them. Let me enlighten you! I found them from a periodic table of elements.

Add those two values together to get a total molecular molar mass of:
38.99g/mol

2.5mol Na2O * ( 38.99 gNa2O / 1 molNa2O) = 97 gNa2O

6 0

2 years ago

For the balanced equation shown below, how many moles of N2 will react with 0.3034 moles of Mg?

olga55 [171]

Answer:

0.1011 moles of N₂

Explanation:

This is the reaction:

3 Mg + N₂ → Mg₃N₂

3 moles of magnesium can react to 1 mol of nitrogen in order to produce 1 mol of magnesium nitride.

We can solve this by a rule of three:

3 mol of Mg need 1 mol of N₂ for the reaction

Then, 0.3034 moles of Mg may react to (0.3034 . 1) / 3 = 0.1011 moles of nitrogen.

The stoichiometry is 3:1

7 0

2 years ago

What would happen to the density of an ideal gas if its pressure is cut in half and its Kelvin temperature decreases by 10 times

inysia [295]

Answer:

The density increases by 5 times

Explanation:

We can solve this problem by using the equation of state of an ideal gas:

$pV=nRT$

where

p is the pressure of the gas

V is its volume

n is its number of moles

R is the gas constant

T is the Kelvin temperature

Since n and R are constant during a gas transformation, we can rewrite the equation as

$\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}$

In thhis problem we have:

$p_2=\frac{p_1}{2}$ , since the pressure of the gas is cut in half

$T_2=\frac{T_1}{10}$ , since the gas temperature decreases by 10 times

Therefore solving for V2, we find how much does the volume of the gas change:

$V_2=\frac{p_1 V_1 T_2}{p_2 T_1}=\frac{p_1 V_1 (T_1/10)}{(p_1/2) T_1}=\frac{V_1}{5}$

So, the volume decreases by 5 times.

The density of the gas is given by

$d=\frac{m}{V}$

where m is the mass of the gas and V its volume. Here, the mass of the gas remains constant: so, the density is inversely proportional to the volume. Therefore, if the volume decreases by 5 times, the density will increase by 5 times.

5 0

2 years ago

Oxygen is not a large part of the air used by organisms in respiration therefore it is not an important element.

Rudik [331]

Answer

false

explanation

air is the most important element in respiration

6 0

10 months ago

Help please I really need it.

Naddik [55]

Answer:

Read image

Explanation:

7 0

2 years ago