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4 years ago

What happens to pressure as volume increases

2 answers:

7 0

Answer: So if the volume increases, the pressure decreases. ... Boyle's law states that for a fixed amount of gas in an enclosed system at constant temperature, pressure and volume are inversely proportional

Explanation:

This linear relationship between pressure and volume means doubling the volume of a given mass of gas decreases its pressure by half.

PV = c

P ∝ 1/V

Colt1911 [192]4 years ago

4 0

If the volume increases then the pressure would decrease.

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Identify the solution that contains both the solute and solvent in the solid phase. A) air B) NaCl C) bronze D) salt water

Iteru [2.4K]

Answer:prolly c

Explanation:

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3 years ago

A sample of gas A has a molar mass of 4 grams while a sample of gas B has a molar mass of 16 grams. Which statement holds true?

jeka94

I believe the closest possible answer to this question are:Gas A effuses faster than gas B.The molar mass is directly proportional to the rate of effusion.Thank you for your question. Please don't hesitate to ask in Brainly your queries

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4 years ago

Read 2 more answers

An aluminum block has a density of 2.70 g/mL. If the mass of the block is 24.60 g, find the volume of the substance.

harina [27]

Volume of a substance can be determined by dividing mass of the substance by its density.

That can be mathematical shown as:

Density=Mass/Volume

So, Volume=Mass/Density

Here mass of the substance given as 24.60 g

Whereas density of the substance is 2.70 g/mL

So,

Volume=Mass/Density

=24.6/2.7

=9.1 mL

So volume of the substance is 9.1 mL.

8 0

3 years ago

For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →

Vinvika [58]

Answer : The oxidizing element is N and reducing element is O.

$KNO_{3}$ is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

$KNO_{3}$ act as an oxidizing agent.

The oxidation number of N in $KNO_{3}$ is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in $KNO_{2}$ is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number reduced this means $KNO_{3}$ itself get reduced to $KNO_{2}$ and it can act as an oxidizing agent.

$KNO_{3}$ act as a reducing agent.

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

The oxidation number of O in $KNO_{3}$ is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in $O_{2}$ is Zero (o).