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Radda [10]
4 years ago
11

Is arsenic malleable?

Chemistry
2 answers:
alexdok [17]4 years ago
8 0
Yes..it is malleable
Vaselesa [24]4 years ago
7 0
Yes it is. Hope this helps
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How to get 1m solution to 0.001m solution?
lyudmila [28]
By calculating the answer
7 0
4 years ago
Plz help plz help plz help meed
Leviafan [203]

Answer:

5106.38 Ω

Explanation:

From the question given above, the following data were obtained:

Current (I) = 0.0235 A

Voltage (V) = 120 V

Resistor (R) =?

From ohm's law,

V = IR

Where:

V => is the voltage.

I => is the current

R => is the resistor

With the above formula, we can obtain the size of the resistor needed as follow:

Current (I) = 0.0235 A

Voltage (V) = 120 V

Resistor (R) =?

V = IR

120 = 0.0235 × R

Divide both side by 0.0235

R = 120 / 0.0235

R = 5106.38 Ω

Thus, the size of the resistor needed is 5106.38 Ω

3 0
3 years ago
Which describes data that is faked or misplaced?
jeka94

Answer: can you give me and passage?

Explanation:

3 0
4 years ago
Read 2 more answers
Teo3 lewis structure
svetoff [14.1K]

Answer:

here. hope it helps!

Explanation:

5 0
1 year ago
Help please! A gas occupies 500 mL at 270 mm Hg and 55°C. If the pressure is changed to 1.8 atm and the temperature is
NNADVOKAT [17]

Answer:

V₂ = 112.14 mL

Explanation:

Given data:

Initial volume = 500 mL

Initial pressure = 270 mmHg (270/760 =0.355 atm)

Initial temperature = 55 °C (55 +273 = 328 K)

Final temperature = 100°C (100+273 = 373 K)

Final volume = ?

Final pressure = 1.8 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 0.355 atm × 500mL × 373 K / 328 K × 1.8 atm

V₂ = 66207.5 atm .mL. K /  590.4 K.atm

V₂ = 112.14 mL

6 0
4 years ago
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