By calculating the answer
Answer:
5106.38 Ω
Explanation:
From the question given above, the following data were obtained:
Current (I) = 0.0235 A
Voltage (V) = 120 V
Resistor (R) =?
From ohm's law,
V = IR
Where:
V => is the voltage.
I => is the current
R => is the resistor
With the above formula, we can obtain the size of the resistor needed as follow:
Current (I) = 0.0235 A
Voltage (V) = 120 V
Resistor (R) =?
V = IR
120 = 0.0235 × R
Divide both side by 0.0235
R = 120 / 0.0235
R = 5106.38 Ω
Thus, the size of the resistor needed is 5106.38 Ω
Answer: can you give me and passage?
Explanation:
Answer:
V₂ = 112.14 mL
Explanation:
Given data:
Initial volume = 500 mL
Initial pressure = 270 mmHg (270/760 =0.355 atm)
Initial temperature = 55 °C (55 +273 = 328 K)
Final temperature = 100°C (100+273 = 373 K)
Final volume = ?
Final pressure = 1.8 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.355 atm × 500mL × 373 K / 328 K × 1.8 atm
V₂ = 66207.5 atm .mL. K / 590.4 K.atm
V₂ = 112.14 mL
