Gibb free energy of activation is = -RT in K
R= gas constant=8.314 j/mol
T=temperature= 500+273= 773 K
K=rate constant
gibb free energy is therefore= - 8.314 j/mol /k x 773k in 5.95 x10^-4= 471730.94j/mol
Answer:
ask them. it doesn't really hurt to.
Answer:-
500324 grams
Explanation:-
Heat absorbed Q = M x Cp x T
We are given T = 10 [ The maximum allowed temperature increase]
Plugging in the values
6.70 x 10^ 6 J = M x 30.8 J / (K mol) x 10 K
M = 6.70 x 10 ^6 / (30.8 x 10)
= 21753 moles
Atomic Mass of sodium =23 gram / mol
Grams of liquid sodium required = 21753 moles x 23 grams / mol
= 500324 grams
Salt and water
Sugar and water
Kool-aid and water