The reagents which are used to carry out the chlorination of benzene are cl2/fecl3 and cl2/nacl
Chlorination is the process of disinfecting drinking water by introducing chlorine to eradicate viruses, germs, and parasites. To get drinking water with safe levels of chlorine, various techniques can be utilized. Chlorination is the technique of disinfecting and eradicating bacteria from drinking water by adding chlorine to it.
To get drinking water with safe levels of chlorine, various techniques can be utilized. Chlorine can be found as solid calcium hypochlorite (Ca(OCl)2), sodium hypochlorite solution (NaOCl), or compressed elemental gas. Chlorine is added to water as part of the chlorination process, however the chlorinating substance need not be pure chlorine.
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Answer:
D. Food poisoning, Bacteria Vomiting, loose stools
Answer:
Formula and structure: The chemical formula of calcium chloride is CaCl2, and its molar mass is 110.983 g/mol. It is an ionic compound consisting of the calcium cation (Ca2+) and two chlorine anions (Cl-). The bivalent calcium metal forms an ionic bond with two chlorine atoms, as shown below.
Answer:
V = 12.93 L
Explanation:
Given data:
Number of moles = 0.785 mol
Pressure of balloon = 1.5 atm
Temperature = 301 K
Volume of balloon = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values.
V = nRT/P
V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm
V = 19.4 L /1.5
V = 12.93 L
Answer:

Explanation:
<u>The alkaline solution: </u>
40 ml of 0.1 M KOH

<u>The acid solution: </u>
30 ml of 0.1 M HCl

The neutralization reaction:

For 1 mol of HCl, 1 mol of KOH is consumed. If 0.003 mol of HCl are added, 0.003 mol of KOH reacted.
After titration:


Concentration (don't forget to add the volumes)

Calcualtion of the pOH:
![pOH=-log([OH^-])=-log(0.0143)=1.84](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%29%3D-log%280.0143%29%3D1.84)
For the pH:
