Answer:
v = 54 m/s
Explanation:
Given,
The maximum height of the flight of golf ball, h = 150 m
The velocity at height h, u = 0
The velocity of the golf ball right before it hits the ground, v = ?
Using the III equations of motion
<em> v² = u² + 2gh</em>
Substituting the given values in the above equation,
v² = 0 + 2 x 9.8 x 150 m
= 2940
v = 54 m/s
Hence, the speed of the golf ball right before it hits the ground, v = 54 m/s
Answer:
They are Transverse Waves.
No it all takes 9 or 10 months
Answer: 
Explanation:
Given
The velocities of the protons are 400 m/s and 450 m/s
Mass of the Proton is 
Since they travel in the opposite direction, therefore, their momentum cancels out each other.
Momentum is the product of mass and velocity

The direction of momentum is in the direction of proton having 450 m/s velocity.
That thing is used as a lever.