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Akimi4 [234]
3 years ago
5

Does out-of-order makea machine's performance more or less

Computers and Technology
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

It would be correct to say that out-of-order makes a machine's performance more sensitive to branch prediction accuracy.

Explanation:

This can be explained as when a machine is out-of-order, in that state the  execution holds importance in prediction accuracy, any increase in these results in rate of prediction near about 25% for the single-issue operating in-order. This is due to the reason that some of the predictions are required for the global pattern history. Most recent outcomes are recorded in the register and for a 4-way machine which is out-of-order, accuracy is very poor as a result of the delay of the branch history for next prediction.

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Read 2 more answers
Assuming a user enters 25 as input, what is the output of the following code snippet? int i = 0; Scanner in = new Scanner(System
Dmitry_Shevchenko [17]

Answer:

The correct answer for the given question is 24

Explanation:

In the given  question the value of variable i entered by the user is 25 i.e the value of i is 25 control checks the condition of if block which is false .So control moves to the else block and executed the condition inside the else block means it executed i-- decrements the value of i by 1 means i is 24

Following are the program of java :

import java.util.*;// import package

public class Main // main class

{

// main method

public static void main(String[] args)

{

int i = 0;  // variable declaration

Scanner in = new Scanner(System.in); // creating class of scanner class

System.out.print("Enter a number: ");

i = in.nextInt();  //  user input

if (i > 25)  // check if block

{

i++; // increment the value of i

}

else

{

   i--; // decrement the value of i

}

System.out.println(i);  // display i

}

}

Output:

Enter a number:25

24

8 0
3 years ago
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