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4 years ago

To move a heavy couch across a carpeted floor what could be used to decrease the frictional force

Physics

2 answers:

vitfil [10]4 years ago

7 0

Use a piece of cardboard

aleksklad [387]4 years ago

3 0

Put a lubricant between the surface of the object and the floor. use round objects, like pencils, to decrease the friction and push the refrigerator over the pencils

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Select the correct answer.

Marianna [84]

Answer:

Explanation:

According to Newton's second law, acceleration is directly proportional to the net force. As the acceleration increases (when mass is constant), the net force increases. This is represented in the following formula.

$f = ma$

$a = \frac{f}{m}$

a = acceleration

f = force

m = mass

6 0

4 years ago

Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with

Mekhanik [1.2K]

Answer: 0.013 seconds

Explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds

8 0

4 years ago

The moon completes one orbit of earth every 27.3 earth days that is its

marishachu [46]

Could be c because it matches the question

7 0

3 years ago

Read 2 more answers

An electric motor rotating a workshop grinding wheel at a rate of 1.31 ✕ 102 rev/min is switched off. Assume the wheel has a con

antoniya [11.8K]

(a) 4.03 s

The initial angular velocity of the wheel is

$\omega_i = 1.31 \cdot 10^2 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=13.7 rad/s$

The angular acceleration of the wheel is

$\alpha = -3.40 rad/s^2$

negative since it is a deceleration.

The angular acceleration can be also written as

$\alpha = \frac{\omega_f - \omega_i}{t}$

where

$\omega_f = 0$ is the final angular velocity (the wheel comes to a stop)

t is the time it takes for the wheel to stop

Solving for t, we find

$t=\frac{\omega_f - \omega_i }{\alpha}=\frac{0-13.7 rad/s}{-3.40 rad/s^2}=4.03 s$

(b) 27.6 rad

The angular displacement of the wheel in angular accelerated motion is given by

$\theta= \omega_i t + \frac{1}{2}\alpha t^2$

where we have

$\omega_i=13.7 rad/s$ is the initial angular velocity

$\alpha = -3.40 rad/s^2$ is the angular acceleration

t = 4.03 s is the total time of the motion

Substituting numbers, we find

$\theta= (13.7 rad/s)(4.03 s) + \frac{1}{2}(-3.40 rad/s^2)(4.03 s)^2=27.6 rad$

6 0

3 years ago

The angle between the incident ray and the surface of a plane mirror is 20'. What is the total angle rotated by the incident ray

Dahasolnce [82]

Angle made by the light ray with the surface of mirror is given as

$\theta_i = 90 - 20 = 70$ degree

now as we know as per law of reflection that

angle of incidence = angle of reflection

So here we can say that

$\theta_i = \theta_r$

$\theta_r = 70 degree$

now the total angle that reflected ray will rotate with respect to incident ray is known as angle of deviation

$\delta =180 - \theta_i - \theta_r$

$\delta = 180 - 70 - 70 = 40 degree$

so here reflected light will deviate by total angle of 40 degree fron its incident ray.

7 0

4 years ago