B long board because of the length
The given reaction is an exothermic reaction due to the negative amount of enthalpy. In this case, an increase in temperature favors the backward reaction which points to the creation of more products. The expression of K or Q is products over reactants concentration. When this happens, Q becomes smaller then. Hence answer is C and 1.
- The equivalent capacitance between point a and b is 5.87μf.
- The charge at 20μf is 93.92 μC.
- The charge at 6μf is 67.8 μC.
- The charge at C and 3μf is 26.12 μC.
<h3>
Sum of capacitance of C and 3μF</h3>
The sum of the capacitance is calculated as follows;
1/Ct = 1/C + 1/3
1/Ct = 1/10μf + 1/3μf
1/Ct = (3μf + 10μf)/30μf²
1/Ct = 13μf/30μf²
Ct = 30μf²/13μf
Ct = 2.31μf
<h3>Total capacitance in parallel arrangement</h3>
The total capacitance in parallel arrangement is calculated as follows;
Ct = 2.31μf + 6μf = 8.31μf
<h3>Equivalent capacitance between point a and b</h3>
1/Ct = 1/8.31μf + 1/20μf
1/Ct = 0.1703
Ct = 5.87μf
<h3>Charge flowing in each capacitor</h3>
Maximum voltage is delivered in 20μf, q = CV
<u>charge for 20μf:</u>
q = (5.87 x 16)μC
q = 93.92 μC
<h3>Equivalent capacitance for C, 3μf and 6μf</h3>
Ct = 2.31μf + 6μf = 8.31uf
<u>charge for 6μf:</u>
q = (6/8.31) x 93.92μC
q = 67.8μC
<h3>Total charge for C and 3μf</h3>
q = 93.92μC - 67.8μC = 26.12 μC
charge for C = charge 3μf = 26.12 μC
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Answer:
A. a balance and a beaker of water
Explanation:
The balance is for mass.
The beaker of water is for volume.