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nikdorinn [45]
3 years ago
11

Why does compound pendulum have the identity of possessing two values of h corresponding to the same period of oscillation

Physics
1 answer:
Amanda [17]3 years ago
8 0

Answer: The compound pendulum

Let G be the center of gravity of a compound pendulum of mass m that oscillates about a point O with OG = h If the pendulum is moved so that the line OG is displaced through an angle θ (Figure 1), the restoring couple is: ... where k is the radius of gyration about a parallel axis through G.

Explanation:

Hope This Helps!!! : )

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Andrej [43]
<span>
The taut guitar string haspotencial energy which we can see in action.</span>  <span>· so option a is correct.</span>
6 0
3 years ago
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[04.05] An atom has an atomic number of 12 and a mass number of 25. How many neutrons does the atom have?​
gizmo_the_mogwai [7]

Answer: is  13

Explanation:

6 0
3 years ago
A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the
Maurinko [17]

Answer:

(a). The decay constant is 1.55\times10^{-5}\ s^{-1}

The half life is 11.3 hr.

(b). The value of N₀ is 2.38\times10^{11}\ nuclei

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity R_{0}=10\ mCi

Time t_{1}=4\ hours

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

R=R_{0}e^{-\lambda t}

\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})

Put the value into the formula

\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})

\lambda=0.0000154\ s^{-1}

\lambda=1.55\times10^{-5}\ s^{-1}

We need to calculate the half life

Using formula of half life

T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}

Put the value into the formula

T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}

T_{\dfrac{1}{2}}=44.719\times10^{3}\ s

T_{\dfrac{1}{2}}=11.3\ hr

(b). We need to calculate the value of N₀

Using formula of N_{0}

N_{0}=\dfrac{3.70\times10^{6}}{\lambda}

Put the value into the formula

N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}

N_{0}=2.38\times10^{11}\ nuclei

(c). We need to calculate the sample's activity

Using formula of activity

R=R_{0}e^{-\lambda\times t}

Put the value intyo the formula

R=10e^{-(1.55\times10^{-5}\times30\times3600)}

R=1.87\ mCi

Hence, (a). The decay constant is 1.55\times10^{-5}\ s^{-1}

The half life is 11.3 hr.

(b). The value of N₀ is 2.38\times10^{11}\ nuclei

(c). The sample's activity is 1.87 mCi.

4 0
3 years ago
When there is no number in front of a chemical formula in a chemical equation, what number is understood?
Andre45 [30]
<span>The number in front is the number of molecules (or atoms) taking part in the (balanced) chemical reaction equation.</span>
5 0
3 years ago
Calculate What is the atomic number of<br> a sodium atom that has 11 protons and 12 neutrons
miv72 [106K]

Answer:

11 because the number of protons is the atomic humber

Explanation:

8 0
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