Answer:
a. 7.62cm
b. Real and inverted
c. 2.76 cm
d. 3450
Explanation:
We proceed as follows;
a. the lens equation that relates the object distance to the image distance with the focal length is given as follows;
1/f = 1/p + 1/q
making q the subject of the formula;
q = pf/p-f
From the question;
p = 4.70m
f = 7.5cm = 0.075m
Substituting these, we have ;
q = (4.7)(0.075)/(4.7-0.075) = 0.3525/4.625 = 0.0762 = 7.62 cm
b. The image is real and inverted since the image distance is positive
c. We want to calculate how tall the image is
Mathematically;
h1 = (q/p)h0
h1 = (7.62/4.70)* 1.7
h1 = 2.76 cm
d. We want to calculate the number of pixels that fit into this image
Mathematically:
n = h1/8 micro meter
n = 2.76cm/8 micro meter = 2.76 * 10^-2/8 * 10^-6 = 3450
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
- A certain circuit is composed of two series resistors
- The total resistance is 10 ohms
- One of the resistor is 4 ohms
<h3>
<u>To </u><u>Find </u><u>:</u><u>-</u></h3>
- We have to find the value of other resistor?
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
We know that,
In series combination,
- When a number of resistances are connected in series, the equivalent I.e resultant resistance is equal to the sum of the individual resistances and is greater than any individual resistance
<u>That </u><u>is</u><u>, </u>
Rn in series = R1 + R2 + R3.....So on
<u>Therefore</u><u>, </u>
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
We have,
R1 + R2 = 10 Ω
4 + R2 = 10Ω
R2 = 10 - 4
R2 = 6Ω
Hence, The value of R2 resistor in series is 6Ω
We know that
g = LcosΘ
<span>where g, L and Θ are centripetal gravity length, and angle of object
</span><span>ω² = g/LcosΘ </span>
<span>ω = √(g / LcosΘ) </span>
