Answer:
1: an elevator moving up to the 3rd floor (gathering potential energy)
2: all options here will increase the GPE
3: the last option
4: just before it hits the ground and has reached a speed of 28 meters per second
5: turning a different direction while moving the same speed
6:a jogger getting faster after spotting a mountain lion behind him on the trail
7: I didn’t watch the lesson
8: at the top of the swinging path, when you are still for a moment just before falling again
9: I d+o)n#t k#n0”w
10: same as 9 sor=ry
Answer:
Explanation:
The period of oscillation will remain unchanged because the period of oscillation of a pendulum does not depend upon the mass of the bob . Here monkey along with bunch of banana represents bob .
When the monkey and banana were at height h /2 , they have potential energy as well as kinetic energy . banana is separated from the system . It carried its total energy along with it . But the energy of monkey remained intact with it . So it will keep on moving as usual . So it will attain the same maximum height as before .
Hence the amplitude of oscillation too will remain unchanged .
Answer:
Velocity 
V = Q + 3Rt²
at t = 0, 
= Q + 3r(0) ==> Q
at t = T, 
= Q + 3rT²
Work done (W) = ΔKE = 
W = ![\frac{1}{2} m[(Q + 3RT^{2})^{2} - Q^{2}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20m%5B%28Q%20%2B%203RT%5E%7B2%7D%29%5E%7B2%7D%20-%20Q%5E%7B2%7D%5D)
W = 
[Q² + 9R²T⁴ + 2Q(3RT²) - Q²]
W = (9R²T⁴ + 6QRT²)
Explanation:
Differentiate the position.
Find the equation for speed.
Find the initial and final speed.
Use work energy theorem to find the work done by finding the change in kinetic energy.
Answer:
0.14 kg
Explanation:
m=F/a = (1.4N/9.8 m/s/s) =0.14 kg
