<span>Suppose you plant a seed and observe that a tree of large mass grows from it. The tree achieves a final mass that changes very little for years afterward.<span>
</span>Answer: Of the options presented above the one that is true about the tree is answer choice B) Both anabolic and catabolic reactions took place in the seed and tree when it was young and growing, and both continue now even though the tree reached a stable mass.
I hope it helps, Regards.</span>
Answer:
δ N2(g) = 1.1825 g/L
Explanation:
- δ ≡ m/v
- Mw N2(g) = 28.0134 g/mol
ideal gas:
∴ P = (837 torr)×( atm/760 torr) = 1.1013 atm
∴ T = 45.0 °C + 273.15 = 318.15 K
∴ R = 0.082 atm.L/K.mol
⇒ n/V = P/R.T
⇒ n/V = (1.1013 atm) / ((0.082 atm.L/K.mol)(318.15 k))
⇒ n/V = 0.0422 mol/L
⇒ δ N2(g) = (0.042 mol/L)×(28.0134 g/mol) = 1.1825 g/L
Answer:
it is a sacrafice to god so the spirtit can go free
Explanation:
<span>17.5 g
35 ppt stands for 35 parts per thousand. So let's convert that to a decimal number by taking 35 and dividing by 1000.
35/1000 = 0.035
Now multiply that number by the number of grams of seawater you have. So
0.035 * 500 g = 17.5 g
So you have 17.5 grams of salt when you have 500 grams of seawater.</span>
