Answer:
![m_{CaCO_3}=0.465g](https://tex.z-dn.net/?f=m_%7BCaCO_3%7D%3D0.465g)
Explanation:
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In this case, since the reaction between two aqueous solutions may turn out in the production of a solid precipitate, for potassium carbonate and calcium chloride, calcium carbonate is precipitated out as shown below:
![CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)](https://tex.z-dn.net/?f=CaCl_2%28aq%29%2BK_2CO_3%28aq%29%5Crightarrow%202KCl%28aq%29%2BCaCO_3%28s%29)
Now, since the two reactants are in a 1:1 mole ratio, we infer they react in the same proportion, thus we compute the reacting moles, considering the used volumes of those molar solutions:
![n_{K_2CO_3}=0.0152L*0.306mol/L=0.00465mol\\\\n_{CaCl_2}=0.0170*0.295mol/L=0.00502mol](https://tex.z-dn.net/?f=n_%7BK_2CO_3%7D%3D0.0152L%2A0.306mol%2FL%3D0.00465mol%5C%5C%5C%5Cn_%7BCaCl_2%7D%3D0.0170%2A0.295mol%2FL%3D0.00502mol)
Thus, since just 0.00465 mol out of 0.00502 moles of calcium chloride are consumed, the potassium carbonate is the limiting reactant, therefore the mass of yielded calcium carbonate (molar mass = 100.09 g/mol) is:
![m_{CaCO_3}=0.00465molK_2CO_3*\frac{1molCaCO_3}{1molK_2CO_3} *\frac{100.09gCaCO_3}{1molCaCO_3}\\\\m_{CaCO_3}=0.465g](https://tex.z-dn.net/?f=m_%7BCaCO_3%7D%3D0.00465molK_2CO_3%2A%5Cfrac%7B1molCaCO_3%7D%7B1molK_2CO_3%7D%20%2A%5Cfrac%7B100.09gCaCO_3%7D%7B1molCaCO_3%7D%5C%5C%5C%5Cm_%7BCaCO_3%7D%3D0.465g)
Best regards!
Correct. Its called noble gas configuration.
The question is whether green bugs or bright red bugs get eaten more often
They can be converted, it's called nuclear transmutation.