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kaheart [24]
3 years ago
12

URGENTE. ¿Qué fuerzas actúan en un tobogán?

Physics
1 answer:
professor190 [17]3 years ago
5 0

Answer:

friction or fricción

if u only speak spanish

Explanation:

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which of the following safety harnesses is the safest and most recommended when hunting from a treestand?
Lyrx [107]

The best tree stand safety harness is the Hunter Safety System Hybrid Flex Safety Harness, with its awesome ElimiShield Scent Control Technology.

Moreover, These stands are designed to be attached directly to the tree. Hunters using a fixed or suspended stand must choose a method of climbing up and down from the platform. The safest and most used method is sectional ladders.

You can learn more about this at:

brainly.com/question/28335498#SPJ4

4 0
11 months ago
What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity o
stira [4]

The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.

<h3>What is the force exerted on the charge?</h3>

Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.

when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.

Mathematically the force exerted on the charge will be

F=qvBsinα

F= force acting on the charge

v = velocity of charge

q = charge

F=qvBsinα

F=2.5×10⁻⁶×5.0×10³×3.0×10²

F=37.5 N

Hence The force acting on the charge will be 3.75 N.

To learn more about the force acting on charge refer to ;

brainly.com/question/451411

F = q V B sinα

Where F is the force applied to a moving charge.

V = charge velocity

q stands for charge.

α = angle between V and B directions

As a result, the moving charge is subjected to a force of 3.75 Newton.

3 0
1 year ago
ALL OF MY POINTS FOR THIS!
scoray [572]
Newton's 2nd law of motion:

                       Force  =  (mass) x (acceleration)

                                   =  (1,127 kg) x (6 m/s² forward)

                                   =  (1,127 x 6)  newtons forward

                                   =    6,762 newtons forward
______________________________

             Momentum  =  (mass) x (speed)

                                 =   (69 kg) x (6 m/s)

                                 =      414 kg-m/s
3 0
3 years ago
As an emergency vehicle approaches Bob and moves away from Jill, how does the actual frequency of the siren change? A) As an eme
Tamiku [17]
The correct answer is: 
<span>C) The actual frequency of the siren does not change despite appearances.

In fact, Bob will observe an increase in the apparent frequency as the emergency vehicle approaches him, while Jill will observe a decrease in the apparent frequency as the emergency vehicle moves away from him, because of the Doppler effect (the relative velocity between the observer and the source of the sound is changing), but this effect involves the apparent frequency, while the real frequency of the siren will remain the same.</span>
7 0
3 years ago
Read 2 more answers
A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the
svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength  is given by

           \lambda = \dfrac{2L}{n}

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

            f = n\dfrac{v}{2L}

now, wavelength calculation

      n = 1

           \lambda_1 = \dfrac{2\times 2}{1}

                    λ₁ = 4 m

      n = 2

           \lambda_2 = \dfrac{2\times 2}{2}

                   λ₂ = 2 m

      n =3

           \lambda_3 = \dfrac{2\times 2}{3}

                    λ₃ = 1.333 m

now, frequency calculation

      n = 1

            f = n\dfrac{v}{2L}

            f_1 =1\times \dfrac{50}{2\times 2}

                    f₁ = 12.5 Hz

      n = 2

            f = n\dfrac{v}{2L}

            f_2 =2\times \dfrac{50}{2\times 2}

                    f₂= 25 Hz

      n = 3

            f = n\dfrac{v}{2L}

            f_3 =3\times \dfrac{50}{2\times 2}

                    f₃ = 37.5 Hz

8 0
3 years ago
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