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netineya [11]
2 years ago
9

How does NaOH form a basic solution when it dissolves in water

Physics
1 answer:
Lubov Fominskaja [6]2 years ago
8 0
It decomposes into CH3COO- and H+ when dissolved in water. The H+ ions react with the water molecules to generate H3O+, making the solution acidic. When NaOH is added to water, it separates into Na+ and OH-. The sodiums have little effect on the solution, but the hydroxyls make it more basic.
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1. How much heat must be absorbed by 375 grams of water to raise its
antiseptic1488 [7]

Answer:

39225J

Explanation:

Given parameters:

Mass of water  = 375grams of water

Change in temperature  = 25°C

Specific heat capacity of water  = 4.184J/g°C

Unknown:

Amount of heat absorbed  = ?

Solution:

To solve this problem, we use the expression below:

      H  = m c Ф  

H is the heat absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

  Insert the parameters and solve;

      H  = 375 x 4.184 x (25) = 39225J

5 0
3 years ago
What is the average acceleration of the object represented in the graph above over the 10 seconds? I know the answer isn’t C
polet [3.4K]

It's always a good idea to start with the definition of the thing you're trying to find.

This problem is just trying to find out whether you KNOW the definition of acceleration. You may know it, but you haven't used it yet.

Average acceleration = (change in velocity) divided by (total time).

Change in velocity = (end value) minus (start value)

Change in velocity = (20m/s) - 0

Change in velocity = 20 m/s

Time = 10 s

Average acceleration = (20m/s)/(10s)

Average acceleration = 2 m/s^2

3 0
3 years ago
Read 2 more answers
A leaf floating down from a tree is an example of an object in free fall.<br> A. True<br> B. False
BlackZzzverrR [31]

Answer:

its false

Explanation:

because if an leaf floats down from a tree it is not considered an object for a free-fall

4 0
3 years ago
Read 2 more answers
A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9
Andreyy89

Answer:

d = 0.0306 m

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

U + K = constant

\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0

7.05 + 30.5 = \frac{0.266}{r}

r = 7.08 \times 10^{-3} m

so distance moved by the particle is given as

d = r_1 - r_2

d = 0.0377 - 0.00708

d = 0.0306 m

6 0
3 years ago
A cart rolling down an incline for 5.0 seconds has an acceleration of 4.0 m/s .If the cart has an initial speed of of 2.0 m/s ,w
Lubov Fominskaja [6]

Applying

v=u+a.t

(all the symbols are bearing their conventional meaning)

Here,u=2ms−1,t=5,a=4ms−2

So,v=2+4⋅5=22ms−1

<h2><u>Mark as Brainliest</u></h2>
8 0
3 years ago
Read 2 more answers
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