Explanation:
A) Use Hooke's law to find the spring constant.
F = kx
40 N = k (0.4 m)
k = 100 N/m
B) Period of a spring-mass system is:
T = 2π √(m / k)
T = 2π √(2.6 kg / 100 N/m)
T = 1 s
Frequency is the inverse of period.
f = 1 / T
f = 1 Hz
<span>The relationship between wavelength, frequency and energy of Electromagnetic Radiation is given by
E = hf = hc/lamba -------(1)
So from (1) there's a linear relationship between E and f. The higher the frequency, f, the higher the energy E.
Also from (1) it is obvious that the lower the wavelength, lambda, the higher the energy, E.
This means the answer is D.</span>
Answer:
Fm - W = 0 1) true. Imams must separate, to match the two forces, you reach equilibrium
Explanation:
When the magnet is exchanged for a stronger one, but of the same weight, the equilibrium equation
Fm - W = 0
Fm = W
If the weight of the imam is the same, the magnetite force must decrease, so that it will occupy the magnets must be separated a greater distance, according to the formula
Fm = Km m ’m / r²
Where Km is value 10⁻⁷ N s²/C², r is the distance between the poles
Let's review the proposed results
1) true. Imams must separate, to match the two forces, you reach equilibrium
2) False. In this case the weight would be less than the magnetic force
3) False The magnetic force increases and equilibrium is not reached
