Paradoxes and Russell's Type Theories.
Simple Type Theory and the λ -Calculus.
Ramified Hierarchy and Impredicative Principles.
Type Theory/Set Theory.
Type Theory/Category Theory.
Extensions of Type System, Polymorphism, Paradoxes.
Univalent Foundations.
Answer:
1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.
Explanation:
Given data:
mass of cadmium = 6.35 g
Number of atoms of aluminum as 6.35 g cadmium contain = ?
Solution:
Number of moles of cadmium = 6.35 g/ 112.4 g/mol
Number of moles of cadmium = 0.06 mol
Number of atoms of cadmium:
1 mole = 6.022×10²³ atoms of cadmium
0.06 mol × 6.022×10²³ atoms of cadmium/ 1mol
0.36×10²³ atoms of cadmium
Number of atoms of Al:
Number of atoms of Al = 0.36×10²³ atoms
1 mole = 6.022×10²³ atoms
0.36×10²³ atoms × 1 mol /6.022×10²³ atoms
0.06 moles
Mass of aluminum:
Number of moles = mass/molar mass
0.06 mol = m/ 27 g/mol
m = 0.06 mol ×27 g/mol
m = 1.62 g
Thus, 1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.
The chemical formula of aluminum chloride is AlCl₃ and the chemical formula of aluminum oxide is Al₂O₃.
<h3>Aluminum chloride</h3>
The chemical formula of aluminum chloride is written as;
Al³⁺ + Cl⁻ → AlCl₃
<h3>Aluminum oxide</h3>
The chemical formula of aluminum oxide is written as;
Al³⁺ + O²⁻ → Al₂O₃
Thus, the chemical formula of aluminum chloride is AlCl₃ and the chemical formula of aluminum oxide is Al₂O₃.
Learn more about chemical formula here: brainly.com/question/26388921
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