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bonufazy [111]
3 years ago
10

Define atomic size, electronegativity, and ionization energy and explain how they vary at different places on the periodic table

.
DONT NEED TO DEFINE THEM, JUST SAY HOW THEY VARY AT DIFFERENT PLACES ON THE PERIODIC TABLE
Chemistry
1 answer:
anygoal [31]3 years ago
5 0
As you move down the periodic table, atomic size increases (due to the number of electron shells of an atom increasing). So in Group 1, H has the smallest atomic size, while Fr has the largest.

Ionization energy tends to decrease as you go down a group, and increase as you go from left to right on the periodic table. (As you go down, the atomic size/radius increases, so the outermost electrons are held less tightly to the nucleus, causing a lower ionization energy.)

Electronegativity relates to ionization energy. Elements with a higher ionization energy will have higher electronegativity. Therefore, as you move down the periodic table, electronegativity decreases, while as you move from left to right on the periodic table, electronegativity increases. 
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Calculate the number of moles of NaOH contained in 250. mL of a 0.05M solution.
steposvetlana [31]

Answer:

0.0125mol

Explanation:

Molarity (M) = number of moles (n) ÷ volume (V)

n = Molarity × Volume

According to this question, a 0.05M solution contains 250 mL of NaOH. The volume in litres is as follows:

1000mL = 1L

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= 0.250L

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The number of moles of NaOH is 0.0125mol.

3 0
3 years ago
4
STALIN [3.7K]

Answer: The space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

Explanation:

Given: V_{1} = 250 mL,    P_{1} = 800 torr,     T_{1} = 50^{o}C

V_{2} = ?,         P_{2} = 400 torr,        T_{2} = 25^{o}C

Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL

Thus, we can conclude that space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

7 0
3 years ago
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