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3 years ago

What is a good analogy for potential energy in a circuit?

Physics

1 answer:

AlexFokin [52]3 years ago

8 0

Answer: find the answer in the explanation

Explanation: The potential energy in a circuit between two points is the workdone in taking units positive charge from one point to the other in the circuit. Its S.I unit is Joule.

Because voltage of a battery or cell in a circuit is the potential energy difference across its terminal

The potential energy difference between two points is one volt, if the workdone in taking one Coulomb of positive charge from one point to the other is one Joule.

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A mine car, whose mass is 440kg, rolls at a speed of 0.50m/s on ahorizontal track, as the drawing shows. A 150kg chunk of coalha

ella [17]

Answer: 0.56 m/s

Explanation:

hello, there is 25° inclination angle for the chute in the drawing. Thankfully, I know this problem. The conservation of momentum.

so there are X and Y components for the momentum in this problem. The Y component is not conserved as when the coal gets in the cart, the normal force exerted by the surface reduces it to 0.

Now, the X component is definitely conserved here.

so you have the momentum of the cart which is 440*0.5 added to the momentum of the chunk which is 150*0.8*cos(25°), that is the momentum before the coupling between the objects. Afterwards both objects will have the same velocity, so we write the equation like this:

$440*0.5 + 150*0.8*cos(25) = 440*v_{final} + 150*v_{final} \\ => 220+120*cos(25) = (440+150)v_{final} => v_{final} = \frac{220+120*cos(25)}{590} = 0.56 m/s$

3 0

3 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

abruzzese [7]

Answer:

(a) 5.73 * 10¹³ m/s²

(b) 4.99 * 10⁵ m/s

Explanation:

(a) We know that Electrical force is the product of electric charge and electric field:

F = qE

We also know that Force is the product of mass and acceleration:

F = ma

Therefore, equating both of them:

ma = qE

Acceleration, a, will be:

a = (qE) / m

Electric charge of a positron = 1.602 * 10^(-19) C

Mass of a positron = 9.11 * 10^(-31) kg

Acceleration will be:

a = (1.602 * 10^(-19)) * 9.11 * 10^(-31)) / 326

a = 5.73 * 10¹³ m/s²

(b) Acceleration is the time rate of change of velocity. It is given as:

a = v/t

Velocity, v, will then be:

v = a * t

Time, t = 8.7 * 10^(-9) s

Therefore, velocity will be:

v = 5.73 * 10^(13) * 8.7 * 10^(-9)

v = 49.85 * 10⁴ m/s = 4.99 * 10⁵ m/s

7 0

3 years ago

How much work is done when a force of 33 N pulls a wagon 13 meters?

kramer

Answer:

Work = (force) x (distance)

Work = (33N) x (13m) = 429 N-m = 429 joules

IF the force is in exactly the same direction as the motion of the wagon.

Explanation:

pa mark ng brainliest

7 0

3 years ago

Consider this acid-base reaction:

sergeinik [125]

Answer:

Explanation:

8 0

2 years ago

All of the following are examples of positive direction except:

charle [14.2K]

Answer:

right

Explanation:

think of a compass theres N.E.S.W north, east, south, west

8 0

3 years ago