Answer:
my opi
Explanation:
Mass is like the inside of the weight. weight is just home much it weighs
Answer:
Explanation:
Given
Distance between two loud speakers ![d=1.6\ m](https://tex.z-dn.net/?f=d%3D1.6%5C%20m)
Distance of person from one speaker ![x_1=3\ m](https://tex.z-dn.net/?f=x_1%3D3%5C%20m)
Distance of person from second speaker ![x_2=3.5\ m](https://tex.z-dn.net/?f=x_2%3D3.5%5C%20m)
Path difference between the waves is given by
![x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}](https://tex.z-dn.net/?f=x_2-x_1%3D%282m%2B1%29%5Ccdot%20%5Cfrac%7B%5Clambda%20%7D%7B2%7D)
for destructive interference m=0 I.e.
![x_2-x_1=\frac{\lambda }{2}](https://tex.z-dn.net/?f=x_2-x_1%3D%5Cfrac%7B%5Clambda%20%7D%7B2%7D)
![3.5-3=\frac{\lambda }{2}](https://tex.z-dn.net/?f=3.5-3%3D%5Cfrac%7B%5Clambda%20%7D%7B2%7D)
![\lambda =0.5\times 2](https://tex.z-dn.net/?f=%5Clambda%20%3D0.5%5Ctimes%202)
![\lambda =1\ m](https://tex.z-dn.net/?f=%5Clambda%20%3D1%5C%20m)
frequency is given by
![f=\frac{v}{\lambda }](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv%7D%7B%5Clambda%20%7D)
where ![v=velocity\ of\ sound\ (v=343\ m/s)](https://tex.z-dn.net/?f=v%3Dvelocity%5C%20of%5C%20sound%5C%20%28v%3D343%5C%20m%2Fs%29)
![f=\frac{343}{1}=343\ Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B343%7D%7B1%7D%3D343%5C%20Hz)
For next frequency which will cause destructive interference is
i.e.
and ![m=2](https://tex.z-dn.net/?f=m%3D2)
![3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda](https://tex.z-dn.net/?f=3.5-3%3D%5Cfrac%7B2%5Ccdot%201%2B1%7D%7B2%7D%5Ccdot%20%5Clambda)
![\lambda =\frac{1}{3}\ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7B1%7D%7B3%7D%5C%20m)
frequency corresponding to this is
![f_2=\frac{343}{\frac{1}{3}}=1029\ Hz](https://tex.z-dn.net/?f=f_2%3D%5Cfrac%7B343%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D1029%5C%20Hz)
for ![m=2](https://tex.z-dn.net/?f=m%3D2)
![3.5-3=\frac{5}{2}\cdot \lambda](https://tex.z-dn.net/?f=3.5-3%3D%5Cfrac%7B5%7D%7B2%7D%5Ccdot%20%5Clambda%20)
![\lambda =\frac{1}{5}\ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7B1%7D%7B5%7D%5C%20m)
Frequency corresponding to this wavelength
![f_3=\frac{343}{\frac{1}{5}}](https://tex.z-dn.net/?f=f_3%3D%5Cfrac%7B343%7D%7B%5Cfrac%7B1%7D%7B5%7D%7D)
Calculate velocity at halfway to the ground.
vfinal = root 2ad
v = root (2*9.81m/s^2*25)
v = 69.367175234 m/s
Kinetic energy = 1/2mv^2
Kinetic energy = 1/2 * (69.367175234 m/s^s^2
Ek = 2405.9025 Joules
As we know that total work done by a force is given by
![W = F.d](https://tex.z-dn.net/?f=W%20%3D%20F.d)
![W = Fdcos\theta](https://tex.z-dn.net/?f=W%20%3D%20Fdcos%5Ctheta)
so it is product of force and displacement along same direction
as we can write it as
![W = (Fcos\theta)(d)](https://tex.z-dn.net/?f=W%20%3D%20%28Fcos%5Ctheta%29%28d%29)
so it must be the product of force and displacement in same directions so correct answer must be
<u>B. in the same direction as the displacement vector and the motion.</u>