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3 years ago

A ball is dropped from 215m. How long will it take to reach the ground? Use 9.8

Physics

1 answer:

valkas [14]3 years ago

7 0

Answer:

The time is $t = 6.62 \ s$

Explanation:

From the question we are told that

The height of the platform where the ball was dropped from is s = 215 m

The acceleration due to gravity is $g = 9.8 \ m/s^2$

Generally from kinematic equations

$s = ut + \frac{1}{2} gt^2$

Here u is the initial velocity of the ball and the value is u = 0 m/s given that the ball was at rest before it was dropped

$21 5 = 0 * t + \frac{1}{2} * 9.8t^2$

=> $21 5 = 4.9t^2$

=> $t^2 = \frac{215}{4.9}$

=> $t = 6.62 \ s$

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If m represent mass in kg, v represents speed in m/s and r represents radius in m show F in the formula F= (mv^2)/r can be expre

Dmitrij [34]

M represent mass in kg
v represents speed in m/s
r represents radius in m

Now, just substitute these into the formula:
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3 years ago

An airplane starts from rest and accelerates at 10.8 m/s2 . what is its speed at the end of a 400 m long runway?

Cloud [144]

The final speed of an airplane is v = 92.95 m/s

The rate of change of position of an object in any direction is known as speed i.e. in other word, Speed is measured as the ratio of distance to the time in which the distance was covered.

Solution-

Here given,

Acceleration a= 10.8 m/s2 .

Displacement (s)= 400m

Then to find final speed of airplane v=?

Therefore from equation of motion can be written as,

v²=u²+ 2as

where, u is initial speed, v is final speed ,a is acceleration and s is displacement of the airplane. Therefore by putting the value of a & s in above equation and (u =0) i.e. the initial speed of airplane is zero.

v²= 2×10.8 m/s²×400m

v²=8640m/s

v=92.95m/s

hence the final speed of airplane v =92.95m/s

To know more about speed

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Severus Snape knows that density of his powder is 3.00 g/cm3 . He also knows he needs 3.00 cm3 of this powder. What mass in gram

harina [27]

Answer:

He requires 1 gram of mass.

Explanation:

The density is defined as:

$\rho = \frac{m}{V}$ (1)

Where m is the mass and V is the volume.

Then, m can be isolated from equation 1 in order to determine the mass.

$m = \rho \cdot V$ (2)

$m = (3.00g/cm^{3})(3.00cm^{3})$

$m = 1g$

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3 years ago

A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration

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To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

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m= Mass

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At the same time the frictional force can be defined as,

$F_f = \mu N$