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3 years ago

A titanium cube contains 3.10•10^23 atoms. The density of a titanium is 4.50g/cm^3. What is the edge length of the cube?

Chemistry

1 answer:

Lerok [7]3 years ago

5 0

Answer:

1.76cm

Explanation:

We'll begin by calculating the mass of titanium that contain 3.10x10²³ atoms. This can be obtained as follow:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10²³ atoms. This implies that 1 mole of titanium also contains 6.02x10²³ atoms.

1 mole of titanium = 48g

Now, if 48g of titanium contains 6.02x10²³ atoms,

Then Xg of titanium will contain 3.10x10²³ atoms i.e

Xg of titanium = (48x3.10x10²³)/6.02x10²³

Xg of titanium = 24.72g

Next, we shall determine the volume of the titanium. This is illustrated below:

Density of titanium = 4.50g/cm³

Mass of titanium = 24.72g

Volume of titanium =..?

Density = Mass /volume

Volume = Mass /Density

Volume of titanium = 24.72g/4.50g/cm³

Volume of titanium = 5.49cm³

Finally we shall determine the edge length of the titanium cube as follow:

Volume = L³

5.49cm³ = L³

Take the cube root of both side

L = 3√(5.49cm³)

L = 1.76cm

Therefore, the edge length is 1.76cm

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A certain liquid has a normal freezing point of and a freezing point depression constant . Calculate the freezing point of a sol

katrin2010 [14]

The question is incomplete, the complete question is:

A certain liquid X has a normal freezing point of $0.80^oC$ and a freezing point depression constant $K_f=7.82^oC.kg/mol$ . Calculate the freezing point of a solution made of 81.1 g of iron(III) chloride () dissolved in 850. g of X. Round your answer to significant digits.

Answer: The freezing point of the solution is $-17.6^oC$

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

$\text{Freezing point of pure solvent}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $0.80^oC$

Freezing point of solution = $?^oC$

i = Vant Hoff factor = 4 (for iron (III) chloride as 4 ions are produced in the reaction)

$K_f$ = freezing point depression constant = $7.82^oC/m$

$m_{solute}$ = Given mass of solute (iron (III) chloride) = 81.1 g

$M_{solute}$ = Molar mass of solute (iron (III) chloride) = 162.2 g/mol

$w_{solvent}$ = Mass of solvent (X) = 850. g

Putting values in equation 1, we get:

$0.8-(\text{Freezing point of solution})=4\times 7.82\times \frac{81.1\times 1000}{162.2\times 850}\\\\\text{Freezing point of solution}=[0.8-18.4]^oC\\\\\text{Freezing point of solution}=-17.6^oC$

Hence, the freezing point of the solution is $-17.6^oC$

6 0

3 years ago

ethanol and benzene dissolve in each other. when ml of ethanol is dissolved in l of benzene, what is the mass of the mixture?

dsp73

The total mass of the mixture will be "958.5 g".

Calculation ,

According to the question, the density of both the mixtures will be:

Ethanol = 0.785 g/mL ( given )

Benzene = 0.880 g/mL ( given )

The volume of both the mixtures,

Ethanol = 100 mL ( given )

Benzene = 1.00 L or 1000 mL ( given )

As we know,

density = mass/volume

now,

The mass of Ethanol will be:

mass = density × volume = 0.785 g/mL × 100 mL

mass = 78.5 g

The mass of Benzene will be:

mass = density × volume = 0.880 g/mL × 1000 mL

mass = 880 g

hence,

The total mass of the mixture = 78.5 g + 880 g = 958.5 g

Missing data ,

density of Ethanol = 0.785 g/mL

density of Benzene = 0.880 g/mL

The volume of both the mixtures,

Ethanol = 100 mL

Benzene = 1.00 L

Learn more about mass of the mixture here:

brainly.com/question/15189339

#SPJ4

8 0

1 year ago

What would it feel like to walk on the surface of the moon??

Cloud [144]

I'm pretty sure it would feel like magic, You could definitely float when you jump

6 0

3 years ago

Read 2 more answers

You throw a barbeque for your friends. Before you start the grill, your propane tank has a pressure of 78 psi. When you’re finis

Dvinal [7]

Answer:

b. 485 kPa

Explanation:

Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:

P1T2 = P2T1

P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas

Where P1 = 74psi

T2 = 20°C + 273.15 = 293.15K

P2 = ?

T1 = (95°F -32) * 5/9 + 273.15 = 308.15K

Replacing:

74psi*293.15K = P2*308.15K

70.4psi

In kPa:

70.4psi * (6.895kPa / 1psi) =

4 0

3 years ago

Please help, I will give brainylest

Anna [14]

Answer:

Explanation:

Divide both of the like fractions, then multiply the answers even if their iregular.

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3 years ago