The final concentration of nitrate is 0.367 M
<h3>Concentration of a substance</h3>
The concentration of a substance is the amount of substance present in a given volume of a solution of that substance.
Concentration = number of moles/ volume
<h3>Equation for the dissociation of potassium nitrate</h3>
KNO3 ---> K+ + NO3-
1 mole of KNO3 produces 1 mole of nitrate
moles of nitrate in a 0.1 M KNO3 solution
- moles = concentration × volume
volume of KNO3 = 50.0 mL= 0.05 L
moles of nitrate = 0.1 × 0.05
moles of nitrate in KNO3 = 0.005
<h3>Equation for the dissociation magnesium nitrate</h3>
- Mg(NO3)2 ---> Mg^2+ + 2 NO3-
1 mole of Mg(NO3)2 produces 2 moles of nitrate ion
moles of Mg(NO3)2 = concentration × volume
volume of solution = 100 mL= 0.1 L
moles of Mg(NO3)2 = 0.1 × 0.25 = 0.025
Moles of nitrate = 0.025 × = 0.05
Total moles of nitrate = 0.05 + 0.005 = 0.055 moles
Total volume of solution = 0.1 + 0.05 = 0.15 L
Concentration of nitrate = 0.055/0.15
Concentration of nitrate = 0.367 M
Therefore, the final concentration of nitrate is 0.367 M
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