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3 years ago

What do you understand by the zero error of a measuring instrument

1 answer:

6 0

"It is a defect in a measuring device (Vernier Callipers & Screw Gauge) & zero error is caused by an incorrect position of the zero point."

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Please help ASAP

Mandarinka [93]

Answer:

5cm by 4cm by 10cm = 200

200 / 10 = 20

20 :>

6 0

3 years ago

In which region of the Sun does energy move as waves that transfer from atom to atom? photosphere corona core radiative zone chr

Tatiana [17]

Answer : Option B) Radiative zone

Explanation : The sun consists of many zones in it. Particularly in the radiative zone, the energy is primarily transported toward the exterior side by the process of radiative diffusion and thermal conduction, rather than by convection. Energy travels through the radiation zone in the form of electromagnetic radiation as photons and energy is transformed from atom to atom.

5 0

4 years ago

Read 2 more answers

Two small charged spheres are 7.59 cmcm apart. They are moved, and the force on each of them is found to have been tripled. How

tiny-mole [99]

Answer:

The two small charged spheres are now 4.382 cm apart

Explanation:

Given;

distance between the two small charged sphere, r = 7.59 cm

The force on each of the charged sphere can be calculated by applying Coulomb's law;

$F = \frac{kq_1q_2}{r^2}$

where;

F is the force on each sphere

q₁ and q₂ are the charges of the spheres

r is the distance between the spheres

$F = \frac{kq_1q_2}{r^2} \\\\kq_1q_2 = Fr^2 \ \ (keep \ kq_1q_2 \ constant)\\\\F_1r_1^2 = F_2r_2^2\\\\r_2^2 = \frac{F_1r_1^2}{F_2} \\\\r_2 = \sqrt{\frac{F_1r_1^2}{F_2}} \\\\r_2 = r_1\sqrt{\frac{F_1}{F_2}}\\\\(r_1 = 7.59 \ cm, \ F_2 = 3F_1)\\\\r_2 = 7.59cm\sqrt{\frac{F_1}{3F_1}}\\\\r_2 = 7.59cm\sqrt{\frac{1}{3}}\\\\r_2 = 7.59cm *0.5773\\\\r_2 = 4.382 \ cm$

Therefore, the two small charged spheres are now 4.382 cm apart.

4 0

4 years ago

An object becomes charged when the atoms in the object gain or lose. True or False

sp2606 [1]

Answer:

True.

Explanation:

When an object's atoms gain or lose electrons, it becomes an ion, becoming charged.

3 0

4 years ago

If the current in the circuit is 10.5 A,

sergiy2304 [10]

Answer:

E) 147 V

Explanation:

Ra+Rb+Rc = 14.0

V = IR

V = (10.5)(14.0)

V = 147 V

7 0

3 years ago