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Lesechka [4]
3 years ago
10

write a correct and complete nuclear equation for the alpha decay of a parent atom having 102 protons and 167 neutrons useing th

e symbols for the elements actually involved in the process?
Chemistry
1 answer:
scZoUnD [109]3 years ago
5 0
Alpha partical is a He nucleus. When decaying alpha particle mass is reduced by 4 and atomic number is reduced by 2.

The actual element which has 102 protons is No (Nobelium). 
Since it has 167 neutrons, the mass = protons + neutrons = 102 + 167 = 269

after an alpha decay, the new element formed has 100 protons which is Fm ( Fermium)

the alpha decaying equation is,

    ₁₀₂²⁶⁹No → ₁₀₀²⁶⁵Fm + ₂⁴α + heat

the total mass and the atomic number( numbe rof protons) must be equal in both sides.




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What is the pH of 1.00 L of a buffer that is 0.110 M nitrous acid (HNO2) and 0.200 M NaNO2? (pKa of HNO2 = 3.40)
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Answer:

pH = 3.65    

Explanation:

given data

pKa of HNO2 = 3.40

nitrous acid (HNO2) = 0.110 M

NaNO2 = 0.200 M

to find out

What is the pH

solution

we get here ph for acidic buffer  that is express as

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put here value and we get

pH = 3.40 + log(0.200÷0.110)

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3 years ago
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Which of the following can be seen as a result of the Earth's tilt?
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miskamm [114]

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Explanation:

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If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

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c = specific heat capacity of substance

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Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

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3 years ago
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