Answer:
We need 128 liters of a gaseous hydrogen bromide
Explanation:
Step 1:
Temperature = 58°C
Pressure = 0.891 atm
Volume ofHydrobromic acid we want to prepare is 3.50 L (1.20M)
Step 2: Calculate moles HBr
Moles HBr = molarity * volule
Moles HBr = 1.20 * 3.50 L
Moles HBr = 4.20 moles HBr
Step 3: Calculate volume of Hydrogen bromide
pV = nRT
V=(nRT)/P
⇒ with V = the volume of gaseous hydrogen bromide = ?
⇒with p = the pressure of the gas = 0.891 atm
⇒ with n = the number of moles of hydrogen bromide = 4.2 moles
⇒ with R = the gasconstant = 0.08206 L*atm / mol*K
⇒ with T = the temperature = 58.0 °C = 273 + 58 = 331 Kelvin
V = (4.2*0.08206*331)/0.891
V = 128 L
We need 128 liters of a gaseous hydrogen bromide
