A gardener can fix acidic soil by adding lime over time.
About 46.1 pounds of apple would be needed per day of the trip.
I managed to extract the complete scenario from the attached image.
The trip is made up of 4 men and 3 women, making a total of 7 people.
Everyone has become accustomed to 1500 calories per day.
The total calories needed per day for 7 persons = 1500 x 7
= 10,500 calories
189 g of apple has only 95 calories, what g of apple will produce 10,500 calories?
= 10,500 x 189/95 = 20,889.67 g of apple
From conversion:
1 g = 0.00220462 pounds
20,889.67 g = 20,889.67 x 0.00220462
= 46.1 pounds of apple
More about dimensional analysis can be found here: brainly.com/question/22015862
Answer:

Explanation:
According to the law of mass action:-
The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.
Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.
The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.
From the reaction given that:-

The expression for the rate is:-
![r=k[P]^2](https://tex.z-dn.net/?f=r%3Dk%5BP%5D%5E2)
Given that;- k=
/Ms
[P] =
M
Thus,

Answer:
As community goes through multiple changes through each stage of succession, it is not in equilibrium.
Explanation:
Equilibrium in ecology refers to a state that occurs such that a small disturbance or change is counter balanced by another change so that the community is restored to its original state.
Answer:
(a) 13.7 g.
(b) 28.91 g.
Explanation:
- molality (m) is the no. of moles of solute dissolved in 1.0 kg of solvent.
∴ m = (no. of moles of solute)/(mass of water (kg))
<em>∴ m = (mass/molar mass of solute)/(mass of water (kg)).</em>
<em />
<u><em>(a) Calculate the mass of CaCl₂·6H₂O needed to prepare 0.125 m CaCl₂(aq) by using 500. g of water.</em></u>
∵ m = (mass/molar mass of CaCl₂·6H₂O)/(mass of water (kg)).
m = 0.125 m, molar mass of CaCl₂·6H₂O = 219.0757 g/mol, mass of water = 500.0 g = 0.5 kg.
∴ 0.125 m = (mass of CaCl₂·6H₂O / 219.0757 g/mol)/(0.5 kg).
∴ mass of CaCl₂·6H₂O = (0.125 m)(219.0757 g/mol)(0.5 kg) = 13.7 g.
<u><em>(b) What mass of NiSO₄·6H₂O must be dissolved in 500. g of water to produce 0.22 m NiSO₄(aq)?</em></u>
∵ m = (mass/molar mass of NiSO₄·6H₂O)/(mass of water (kg)).
m = 0.22 m, molar mass of NiSO₄·6H₂O = 262.84 g/mol, mass of water = 500.0 g = 0.5 kg.
∴ 0.125 m = (mass of NiSO₄·6H₂O / 262.84 g/mol)/(0.5 kg).
∴ mass of NiSO₄·6H₂O = (0.22 m)(262.84 g/mol)(0.5 kg) = 28.91 g.