1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lynna [10]
3 years ago
15

Different between progressive wave and stationary wave​

Physics
1 answer:
patriot [66]3 years ago
7 0
1) Progressive waves are the ones by which all the wave disturbances are carried on further and propelled or transferred forward.

1) Stationary waves are the ones by which all the wave disturbances are not carried on further and propelled or transferred forward.

2) In Progressive waves the energies are equally and efficiently transferred along the travelling waves. Every particle are transferring some kind of energy to a next further particle on the same path, basically most of the energies are lost because of which there's no energy acquired by it.

2) In Stationary or standing waves there's no absolute transfer of any significant amount of energies which are not transferred along a path of the wave. Particles in stationery waves are giving and contributing in energy submission and also acquire some of the energy back because of which the net transferring of energies between the particles in a specific period as nullified.

3) Phases of the progressive waves of the particles in these waves are varying in a continuous manner and have changing values between them.

3) Phases of the Stationary or standing waves of the particles in these waves are not changing and always same to the contrary opposite when placed between the consecutively running sets of nodes (Between two nodes of particles).

4) Progressive waves have no particles which show they're having a rest phase or a permanent rest phase in a medium (particle medium).

4) Stationary waves have significant amount of particles of the medium to show that there having a rest phase or a permanent rest phase at the nodes of those particles.

5) Amplitudes of Progressive waves are totally and completely different particles are neutral and are having same values.

5) Amplitudes of Stationary or Standing waves of the particles in between those tow consecutively sets of nodes in between them and antinodes provided are having different values and vary much more progressively.

6) All of the particles in Progressive waves containing it don't specially cross their given mean positions in a simultaneous manner.

6) All of the particles in Stationary waves containing it frequently and steadily cross their given mean positions in a simultaneous manner.

7) In Progressive waves the particles don't show any attainment of a displacement provided in a maximum amount in a simulations manner.

7) In Stationary waves the particles are showing and exhibiting the attainments of various displacements in a maximum amount in a simultaneous manner.

8) Maximum velocities achieved by Progressive waves are indeed same or similar for all the given particles when they're showing a passing of those given mean positions.

8) Maximum velocities achieved by Stationary waves of those particles when they're crossing their given mean positions are in a continuity of increasement for those particles between those "nodes" and of course the consecutively set "antinodes" further which it's showing a significant decreasement after it corresponds and reaches the second or usually the next nearest node.

9) Progressive waves have crest and troughs in their waves that're moving into a forward direction.

9) Stationary waves have crest and troughs in their waves that're appearing and disappearing in same positions or regions that is , not moving forward in a same direction.

Read more on Brainly.in - https://brainly.in/question/1959503#readmore

You might be interested in
Consider a block on frictionless ice. Starting from rest, the block travels a distance din
sweet [91]

Answer:

<em>The distance is now 4d</em>

Explanation:

<u>Mechanical Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

The acceleration can be calculated by solving for a:

\displaystyle a=\frac{F}{m}

Once we know the acceleration, we can calculate the distance traveled by the block as follows:

\displaystyle d = vo.t+\frac{at^2}{2}

If the block starts from rest, vo=0:

\displaystyle d = \frac{at^2}{2}

Substituting the value of the acceleration:

\displaystyle d = \frac{\frac{F}{m}t^2}{2}

Simplifying:

\displaystyle d = \frac{Ft^2}{2m}

When a force F'=4F is applied and assuming the mass is the same, the new acceleration is:

\displaystyle a'=\frac{4F}{m}

And the distance is now:

\displaystyle d' = \frac{4Ft^2}{2m}

Dividing d'/d:

\displaystyle \frac{d' }{d}=\frac{\frac{4Ft^2}{2m}}{\frac{Ft^2}{2m}}

Simplifying:

\displaystyle \frac{d' }{d}=4

Thus:

d' = 4d

The distance is now 4d

3 0
2 years ago
you push with an 18-N horizontal force on a 5-kg box of coffee resting on a on a horizontal surface. the force of friction on th
KatRina [158]

The acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.

Answer:

Explanation:

As per Newton's second law of motion, acceleration of any object is directly proportional to the net external unbalanced force acting on that object and inversely proportional to the mass of the object.

Since there are two forces acting on the box in opposite direction, the net force will be the difference of horizontal and frictional force acting on the object.

Net force = Horizontal force - Frictional force = 18 N - 8 N = 10 N.

Now, from second law of motion, Acceleration = \frac{Net force}{Mass}

So, acceleration = 10 N /5 kg = 2 m/s².

Since, acceleration exerted by the box is found to be 2 m/s², we can determine the final velocity of the object after 10 seconds using the first equation of motion.

v = u + at, Here v is the final velocity and u is the initial velocity which is zero for the present case. Other parameters like a is found to be 2 m/s² and time is 10 seconds.

So Final velocity v = 0+(2×10)=20 m/s.

And the final position can be determined using the second equation of motion.

s = ut+1/2at²

Final position = (0×10)+(0.5×2×10×10)= 100 m.

So the final position is 100 m.

Thus, the acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.

3 0
2 years ago
2. ____________________________ can cause a stationary object to start moving or a moving object to change its speed or directio
Vikentia [17]

As per Newton's law of inertia we can say every object will move in its state of motion either in the state of rest or will move with same constant velocity until some unbalanced external force will act upon it

so here we have to fill the space which says that stationary object can start or moving object will change its direction only in which case

so here the correct answer should be Unbalanced Force condition we will obtain such situation.

so we have

<u>Unbalance force</u> can cause a stationary object to start moving or a moving object to change its speed or direction or both.

7 0
3 years ago
A solid-propellant rocket has chamber pressure of 6.35 atm with propellant density of 3.8 g/cm3 and burn area of 975 cm2 . Find
cupoosta [38]

Answer:

Explanation:

Given:

P = 6.35 atm

= 1.01 × 10^5 × 6.35

= 6.434 × 10^5 N/m^2

As = 975 cm^2

D = 3.8 g/cm^2

M = 320 kg

Since the propellant volume is equal to the cross sectional area, As times the fuel length, the volumetric propellant consumption rate is the cross section area times the linear burn rate, bs , and the instantaneous mass flow rate of combustion, ms gases generated is equal to the volumetric rate times the fuel density, D

ms = D × As × bs

ms ÷ bs = M/L

M/L = 3.8 × 975

= 3705 g/cm

= 3.705 × 10^6 kg/m^3

Pressure = mass × g/area

= mass/length × time^2

t = sqrt(3.705 × 10^6/6.43 × 10^5)

= 2.4 s

4 0
3 years ago
58.54
Lilit [14]

Answer:

6m/s^2

Explanation:

at=Vf-Vi

a=? a(5)=65-35

t=5 a(5)=30

Vi=35 a(5)/5=30/5

Vf=65 a=6m/s^2

7 0
3 years ago
Other questions:
  • A 10 m long high tension power line carries a current of 20 A perpendicular to Earth's magnetic field of 5.5 x10⁻⁵ T. What is th
    12·1 answer
  • The tendency of an object to resist changes in it motion​
    10·1 answer
  • Compared to its weight on Earth, a 10-kg object on the moon will weigh Question 9 options: less. the same amount. more.
    6·2 answers
  • A fox runs for 12 seconds at a speed of 9.65 m/s. How much distance does it cover? Exact answer, do NOT round.
    9·1 answer
  • A 25kg chair initially at rest on a horizontal floor requires 165 N force to set it in motion. Once the chair is in motion, a 12
    7·1 answer
  • What properties does a loud, shrill whistle have? a.) high amplitude, high frequency
    7·1 answer
  • Plz help me answer this its 1 question will give brainliest
    11·2 answers
  • Which of the following is a phase change?
    11·1 answer
  • Can a magnet attract a pure substance?
    10·1 answer
  • A 10kg box accelerates forward at a rate of 12 m/s^2. What is the force acting on the box?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!