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Lynna [10]
3 years ago
15

Different between progressive wave and stationary wave​

Physics
1 answer:
patriot [66]3 years ago
7 0
1) Progressive waves are the ones by which all the wave disturbances are carried on further and propelled or transferred forward.

1) Stationary waves are the ones by which all the wave disturbances are not carried on further and propelled or transferred forward.

2) In Progressive waves the energies are equally and efficiently transferred along the travelling waves. Every particle are transferring some kind of energy to a next further particle on the same path, basically most of the energies are lost because of which there's no energy acquired by it.

2) In Stationary or standing waves there's no absolute transfer of any significant amount of energies which are not transferred along a path of the wave. Particles in stationery waves are giving and contributing in energy submission and also acquire some of the energy back because of which the net transferring of energies between the particles in a specific period as nullified.

3) Phases of the progressive waves of the particles in these waves are varying in a continuous manner and have changing values between them.

3) Phases of the Stationary or standing waves of the particles in these waves are not changing and always same to the contrary opposite when placed between the consecutively running sets of nodes (Between two nodes of particles).

4) Progressive waves have no particles which show they're having a rest phase or a permanent rest phase in a medium (particle medium).

4) Stationary waves have significant amount of particles of the medium to show that there having a rest phase or a permanent rest phase at the nodes of those particles.

5) Amplitudes of Progressive waves are totally and completely different particles are neutral and are having same values.

5) Amplitudes of Stationary or Standing waves of the particles in between those tow consecutively sets of nodes in between them and antinodes provided are having different values and vary much more progressively.

6) All of the particles in Progressive waves containing it don't specially cross their given mean positions in a simultaneous manner.

6) All of the particles in Stationary waves containing it frequently and steadily cross their given mean positions in a simultaneous manner.

7) In Progressive waves the particles don't show any attainment of a displacement provided in a maximum amount in a simulations manner.

7) In Stationary waves the particles are showing and exhibiting the attainments of various displacements in a maximum amount in a simultaneous manner.

8) Maximum velocities achieved by Progressive waves are indeed same or similar for all the given particles when they're showing a passing of those given mean positions.

8) Maximum velocities achieved by Stationary waves of those particles when they're crossing their given mean positions are in a continuity of increasement for those particles between those "nodes" and of course the consecutively set "antinodes" further which it's showing a significant decreasement after it corresponds and reaches the second or usually the next nearest node.

9) Progressive waves have crest and troughs in their waves that're moving into a forward direction.

9) Stationary waves have crest and troughs in their waves that're appearing and disappearing in same positions or regions that is , not moving forward in a same direction.

Read more on Brainly.in - https://brainly.in/question/1959503#readmore

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You push a shopping cart for fun with a force of 60N. If the shopping cart has a mass of 12kg, what is the
posledela

Answer:

\huge\boxed{\sf a = 5 \ ms^{-2}}

Explanation:

<u>Given:</u>

Force = f = 60 N

Mass = m = 12 kg

<u>Required:</u>

Acceleration = a = ?

<u>Formula:</u>

F = ma

<u>Solution:</u>

Rearranging formula

a = F / m

a = 60 / 12

a = 5 ms⁻²

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>
4 0
3 years ago
When material allow to heat to pass though them rapidly they are known as __________​
Katarina [22]

Answer:

They are conductors/conductive. Materials that can transfer thermal energy well are conductive.

Explanation:

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A long, straight metal rod has a radius of 5.75 cm and a charge per unit length of 33.3 nC/m. Find the electric field at the fol
PIT_PIT [208]

Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a)  at 4.75 cm

b)  at 20.5 cm

c) at 125.0 cm

Given that:

the charge (q) = 33.3 nC/m

= 33.3 × 10⁻⁹ c/m

radius of rod = 5.75 cm

a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

Then, the electric field will be zero.

b) The electric field formula E = \dfrac{kq }{d}

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}

E = 1461.95 N/C

c) The electric field E is calculated as:

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

E = 239.76 N/C

7 0
3 years ago
A vertical cylindrical tank 10 ft in diameter, has an inflow line of 0.3 ft inside diameter and an outflow line of 0.4 ft inside
neonofarm [45]

Answer:

\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}, level is rising.

Explanation:

Since liquid water is a incompresible fluid, density can be eliminated of the equation of Mass Conservation, which is simplified as follows:

\dot V_{in} - \dot V_{out} = \frac{dV_{tank}}{dt}

\frac{\pi}{4}\cdot D_{in}^2 \cdot v_{in}-\frac{\pi}{4}\cdot D_{out}^2 \cdot v_{out}= \frac{\pi}{4}\cdot D_{tank}^{2} \cdot \frac{dh}{dt} \\D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out} = D_{tank}^{2} \cdot \frac{dh}{dt} \\\frac{dh}{dt}  = \frac{D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out}}{D_{tank}^{2}}

By replacing all known variables:

\frac{dh}{dt} = \frac{(0.3 ft)^{2}\cdot (5 \frac{ft}{s} ) - (0.4 ft)^{2} \cdot (2 \frac{ft}{s} )}{(10 ft)^{2}}\\\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}

The positive sign of the rate of change of the tank level indicates a rising behaviour.

6 0
4 years ago
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Lisa [10]

Answer:

Initial velocity, U = 4.5m/s

Explanation:

Given the following data;

Final velocity, v = 12m/s

Time, t = 5 seconds

Acceleration, a = 1.5m/s²

To find the initial velocity, we would use the first equation of motion.

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

12 = U + 1.5*5

12 = U + 7.5

U = 12 - 7.5

Initial velocity, U = 4.5m/s

3 0
3 years ago
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