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3 years ago

What is Newton’s first law

Physics

2 answers:

san4es73 [151]3 years ago

8 0

An object remain at the state of rest or motion unless acted by an external force.

amid [387]3 years ago

6 0

Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

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The eyes of many older people have lost the ability to accommodate, and so an older person’s near point may be more than 25 cm f

tensa zangetsu [6.8K]

Answer:

Smaller refractive power

Explanation:

The refractive power of an eye is the extent to which it can converge or diverge the light rays.

Near point is the the closest point for an eye such that when an object is placed at that point the image it forms is sharp and clearly visible to the eye.

A the person ages, the ciliary muscles of the eyes weakens and as a result the lens contracts and the formation of the image takes place behind the retina instead of forming at the retina.

Thus the near point also increases and the refractive power becomes smaller.

4 0

3 years ago

A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.

Zanzabum

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

k x = m g

$k = \dfrac{mg}{x}$

$k = \dfrac{6.4 \times 9.8}{0.28}$

k = 224 N/m

b) $f = \dfrac{\omega}{2\pi}$

$\omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}$

$f =0.94\ Hz$

c) $v_b = -v cos \omega t$

$v_b = -5.1 \times cos (5.92 \times 0.42)$

$v_b = 4.04\ m/s$

d) $a_{max} = v \omega$

$a_{max} = 4.04 \times 5.92$

$a_{max} =23.94\ m/s^2$

e) $Y =- A sin (\omega t)$

$A = \dfrac{v}{\omega}$

$A = \dfrac{4.04}{5.92}$

A = 0.682 m

$Y =- 0.682 \times sin (5.92 \times 0.42)$

$Y =- 0.42$

Force = $m \omega^2 |Y|$

= $6.4 \times 5.92^2\times 0.42$

F = 94.20 N

4 0

4 years ago

What happens to the water in a confined aquifer if a well or fracture intersects it? its depth in the ground will sink downward.

AURORKA [14]

A confined aquifer is a permeable rock unit found deep underground. It is usually overlain by another relatively impermeable rock or clay. This rock or clay layer limits the movement of the underground water whether into or out of the aquifer.

Since water is a liquid, therefore, is is always seeking a way out to leak.

Based on this, when a confined aquifer intersects with a fracture or a well, the water inside the aquifer will tend to move laterally until it can find a spot to leak from.

Therefore, the answer is "<span>It will move laterally until it finds a way out"</span>

4 0

4 years ago

A skydiver of mass m jumps from a hot air balloon and falls a distance d before reaching a terminal velocity of magnitude v. Ass

ahrayia [7]

Answer:

a) W = ΔK.E + ΔP.E = (mv²/2) - mgd

b) Power supplied by the drag force after the skydiver has reached terminal velocity = mgv

Explanation:

Using the work energy theorem, the work done by the drag force while the skydiver moves through a distance d is equal to the change in kinetic energy and potential energy of the body.

The potential energy of the skydiver drops by a magnitude of (mgd) falling through a distance of d.

ΔP.E = - mgd (skydiver loses this amount of potential energy)

But the skydiver falls from rest to gain a velocity of v after falling a distance of d vertically.

ΔK.E = (final kinetic energy at distance d) - (initial kinetic energy at rest)

Final kinetic energy at d = (1/2)(m)(v²) (the body is now falling with terminal velocity (v) at this point d)

Initial kinetic energy = 0 (since the skydiver was initially at rest)

ΔK.E = (1/2)(m)(v²) - 0 = (mv²/2)

W = ΔK.E + ΔP.E = (mv²/2) - mgd

b) At terminal velocity, the net force on the skydiver = 0

hence,

drag force = weight of the skydiver = mg

Power = F × v = mg × v = mgv

Hope this Helps!!!

5 0

3 years ago

If a train travel from Addis Ababa to Dire Dawa at a constant velocity of 400Km/hr and the to Djibouti at a constant velocity of

madreJ [45]

The value of V is 640 km/hr.

<h3>What is Average velocity?</h3>

Average velocity is the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.

To calculate the value of V from the question, we use the formula below.

V' = (V+U)/2............ Equation 1

Making V the subject of the equation

V = 2V'-U.............. Equation 2

From the question,

⇒ Given:

V' = 520 km/hr
U = 400 km/hr

Substitute these values into equation 2

V = (520×2)-400
V = 640 km/hr

Hence, the value of V is 640 km/hr.

Learn more about average velocity here: brainly.com/question/4931057

#SPJ1

4 0

2 years ago