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LekaFEV [45]
2 years ago
11

Where does body heat come from?

Physics
2 answers:
ruslelena [56]2 years ago
8 0

Friction produces heat

Gemiola [76]2 years ago
6 0

Answer:

friction

Explanation:

because everyday our body parts often ended up rubbing each other, by walking and making every single move which is due to friction and this leads to heat.

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A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in
algol [13]

Answer: Magnitude of the force exerted on the egg by the ground is 9.2N

Explanation:

Given the following :

Mass of egg (m) = 150g = 0.15kg

Height(h) from which egg is dropped = 3m

velocity of egg before hitting the ground (u) = 4.4m/s

Final velocity of egg (V) = 0

Time taken (t) = 0.072s

Magnitude of the force exerted on the egg by the ground can be found by applying Newton's 2nd law:

Momentum = mass × velocity

From Newton's second law:

Force = mass × change in Velocity with time ;

That is

F = m * ΔV / t

Inputting our values

F = 0.15 * (4.4 - 0) / 0.072

F = 0.15 × (4.4 / 0.072)

F = 0.15 × 61.11

F = 9.16N

F = 9.2N

8 0
2 years ago
A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic
Umnica [9.8K]

Answer:

<em>A = 6.9 cm</em>

Explanation:

<u>Simple Harmonic Motion</u>

A mass-spring system is a common example of a simple harmonic motion device since it keeps oscillating when the spring is stretched back and forth.

If a mass m is attached to a spring of constant k and they are set to oscillate, the angular frequency of the motion is

\displaystyle w=\sqrt{\frac{k}{m}}

The equation for the motion of the object is written as a sinusoid:

\displaystyle X=A\ cos\ w\ t

Where A is the amplitude.

The instantaneous speed is computed as the derivative of the distance

\displaystyle X'=V=-A\ w\ sin\ w\ t

And the maximum speed is

\displaystyle V_{max}= A\ w

Solving for the amplitude

\displaystyle A= \frac{V_{max}}{w}

Computing w

\displaystyle w =\sqrt{\frac{120}{0.2}}=24.5\   rad/ s

Calculating A

\displaystyle A=\frac{1.7}{24.5}=0.069\ m

\displaystyle \boxed{A=6.9\ cm}

7 0
3 years ago
A car owner forgets to turn off the headlights of his car while it is parked in his garage. If the 12.0-V battery in his car is
avanturin [10]

Answer: 22.6 hours

Explanation:

The power is the measure of the rate of energy.

In this problem, the 12.0 V battery is rated at 51.0 Ah, which means it delivers 51.0 A of current in a time of t = 1 h = 3600 s. The power delivered by the battery can be written as

P=IV

where

I is the current

V = 12.0 V is the voltage of the battery

So the energy delivered by the battery can be written as

E=Pt=VIt

Where

It=51.0 A\cdot h = 51.0 A \cdot 3600 s/h=183,600 A\cdot s

So the energy delivered is

E=(12.0)(183,600)=2.2\cdot 10^6 J

At the same time, the headlight consumes 27.0 W of power, so 27 Joules of energy per second; Therefore, it will remain on for a time of:

t=\frac{2.2\cdot 10^6 J}{27.0 W}=81481 s = 22.6 h

3 0
3 years ago
A tow truck exerts a net horizontal force of 1050 N on a 760-kg car. What is the acceleration of the car during this time?
vovikov84 [41]
We can solve the problem by using Newton's second law of motion:
F=ma
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object

In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
a= \frac{F}{m}= \frac{1050 N}{760 kg}=1.4 m/s^2

The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>B) 1.4 m/s2 horizontally.</span>
5 0
3 years ago
Two loudspeakers emit 600 Hz Hz notes. One speaker sits on the ground. The other speaker is in the back of a pickup truck. You h
Firdavs [7]

Answer:

The truck's speed is 4.04 m/s.

Explanation:

Given that,

Emit frequency = 600 Hz

Beat = 7.00 beat/sec

We need to calculate the truck's speed

Using formula of speed

\text{frequency observed}=\text{frequency emitted}\times\dfrac{v}{v+v_{source}}

Where, v = speed of sound

Put the value into the formula

(600-7)=600\times(\dfrac{343}{343-v_{truck}})

v_{truck}=\dfrac{600\times343-593\times343}{593}

v_{truck}=4.04\ m/s

Hence, The truck's speed is 4.04 m/s.

3 0
2 years ago
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