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Fofino [41]
3 years ago
8

A flashlight bulb is connected to a square loop of wire that measures cm on a side as shown in the figure below. assume the bulb

will only light if the potential across its terminals is at least v. the loop is oriented perpendicular to a uniform magnetic field of t. the magnetic field then decreases to zero over a period of time such that the bulb is just barely lit
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
Mmmmmmmm Ф↓⇄㏑㏒,,⇆↑aaaaaaa
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A stunt woman of mass m falls into a net during the filming of an action movie. Assume she experiences upward acceleration magni
Rashid [163]

Answer:

M= F^n / a+g

Explanation:

This shows correctly Newton’s second law, where sum of forces is divided by mass is equal to acceleration. Also mass can’t be negative so F^n is positive.

8 0
3 years ago
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A ball rolls forward in the grass slowing down as it rolls?
olga nikolaevna [1]

Yes it does, uh huh.  It slows down as it rolls.  That's a fact.

In order for the ball to roll forward, it has to push grass out of the way.  That takes energy.  To bend each blade of grass out of its way, the ball has to use a tiny bit of the kinetic energy that it has, so it gradually runs out of kinetic energy.  When its kinetic energy is all gone, it stops moving.

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3 years ago
The legend that Benjamin Franklin flew a kite as a storm approached is only a legend; he was neither stupid nor suicidal. Suppos
UNO [17]

Answer:

The current on the water layer = 1.64×10^-3A

Explanation:

Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:

I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)

I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)

I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566

I = 252.83 -(4.623×10^-6)/ 154566

I = 252.83/154566

I = 1.64× 10^-3A

3 0
3 years ago
Calculate the current through the ammeter (look at photo)
AleksAgata [21]

Answer:

6 amps

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8 0
1 year ago
put the following in order of a full lunar month: full moon, new moon, 1st quarter, waxing gibbous, waning gibbous, waxing cresc
ASHA 777 [7]

The same cycle of phases repeats over and over and over and over and over again, so I could start the list with whatever phase I want, and build the list until I get to the same phase I  started with.  

But the cultures that track their months by the phases of the Moon (traditional Muslim, traditional Jewish, traditional Chinese) all start the new month with the New Moon, so I guess I'll start my list there too.

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-- Waxing Gibbous

-- Full Moon

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4 0
3 years ago
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