Answer:
a

b

Explanation:
Considering question a
From the question we are told that
The mass of the rocket is
The mass of the fuel which is in the rocket is m = 0.6 M
Generally given that the rocket burns all it fuel in a single stage , the final velocity of the rocket is mathematically represented as
![v_f = v_{ex} ln [\frac{m_o}{m_k} ]](https://tex.z-dn.net/?f=v_f%20%3D%20v_%7Bex%7D%20%20ln%20%5B%5Cfrac%7Bm_o%7D%7Bm_k%7D%20%5D)
Here
is the mass of the rocket without fuel which is mathematically evaluated as

=> 
=> ![m_k = [1- 0.6] m_o](https://tex.z-dn.net/?f=m_k%20%3D%20%20%20%5B1-%20%200.6%5D%20m_o)
=>
=> 
Considering question b
From the question we are told that
The mass of the fuel it burn at the first stage is 
The mass of the first stage fuel tank 
The mass of the fuel at the second stage is 
Generally the velocity of the rocket at the first stage is mathematically represented as
![v_i = v_{ex} * ln [ \frac{m_o }{[1- m]m_o } ]](https://tex.z-dn.net/?f=v_i%20%3D%20v_%7Bex%7D%20%2A%20ln%20%5B%20%5Cfrac%7Bm_o%20%7D%7B%5B1-%20m%5Dm_o%20%7D%20%5D)
=> ![v_i = v_{ex} * ln [ \frac{m_o }{[1- 0.3]m_o } ]](https://tex.z-dn.net/?f=v_i%20%3D%20v_%7Bex%7D%20%2A%20ln%20%5B%20%5Cfrac%7Bm_o%20%7D%7B%5B1-%200.3%5Dm_o%20%7D%20%5D)
=>
=> 
Generally the mass of the rocket after first stage is

=> 
Generally the final velocity of the rocket at the second stage is
![v_f = v_i + v_{ex} * ln [\frac{m_r}{ m_f } ]](https://tex.z-dn.net/?f=v_f%20%3D%20v_i%20%2B%20v_%7Bex%7D%20%2A%20ln%20%5B%5Cfrac%7Bm_r%7D%7B%20m_f%20%7D%20%5D)
=> ![v_f = v_i + v_{ex} * ln [\frac{0.6 m_o }{0.3mo } ]](https://tex.z-dn.net/?f=v_f%20%3D%20v_i%20%2B%20v_%7Bex%7D%20%2A%20ln%20%5B%5Cfrac%7B0.6%20m_o%20%7D%7B0.3mo%20%7D%20%5D)
=> 
=> 
Answer:
C. greater than D, but less than 2D
Explanation:
The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.
The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.
The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...
v2 = v1·√(1/(1/2)) = v1·√2
This means the second mass will land at a distance of about D√2, a value ...
greater than D but less than 2D.
Answer:
I think it is eyeglasses
Explanation:
I think this because the glasses usually reflect the same thing sometimes and the light passes through really easy
Answer:
the power used by the person is 10 W.
Explanation:
Given;
weight lifted, W = 50 N
distance through which the weight was lifted, d = 2 m
time of motion, t = 10 s
The power used by the person is calculated as;

Therefore, the power used by the person is 10 W.
Answer:
:) :) :) :) :) :) :) :) :)
Explanation:
:) :) :) .......