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larisa86 [58]
3 years ago
9

1.05kg of aluminum what is the heat capacity ?

Chemistry
1 answer:
vitfil [10]3 years ago
8 0
The aluminum can with stand <span>0.942 J° C  of heat </span>
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Mg3N2(s)+6H2O(l)→3Mg(OH)2(s)+2NH3(g) When 36.0 g of H2O react, how many grams of NH3 are produced? When 36.0 g of H2O react, how
Afina-wow [57]

Answer:

11.3 g of NH_{3} are produced from 36.0 g of H_{2}O

Explanation:

1. The balanced chemical equation is the following:

Mg_{3}N_{2}(s)+6H_{2}O(l)=3Mg(OH)_{2}(s)+2NH_{3}(g)

2. Use the molar mass of the H_{2}O, the molar mass of the NH_{3} and the stoichiometry of the balanced chemical reaction to find how many grams of NH_{3} are produced:

Molar mass H_{2}O = 18\frac{g}{mol}

Molar mass NH_{3} = 17\frac{g}{mol}

36.0gH_{2}O*\frac{1molH_{2}O}{18gH_{2}O}*\frac{2molesNH_{3}}{6molesH_{2}O}*\frac{17gNH_{3}}{1molNH_{3}}=11.3gNH_{3}

Therefore 11.3 g of NH_{3} are produced from 36.0 g of H_{2}O

3 0
3 years ago
The equilibrium constant for the reaction
FinnZ [79.3K]

Answer: The concentrations of Cl_2 at equilibrium is 0.023 M

Explanation:

Moles of  Cl_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol

Volume of solution = 1 L

Initial concentration of Cl_2 = \frac{0.14mol}{1L}=0.14M

The given balanced equilibrium reaction is,

                            COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial conc.           0.14 M           0 M       0M    

At eqm. conc.     (0.14-x) M        (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}

Now put all the given values in this expression, we get :

4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of Cl_2 at equilibrium is 0.023 M

7 0
3 years ago
25,000cg is equal to _g
defon

Answer:

250 g

Explanation:

8 0
3 years ago
WHAT IS THE CHEMICAL NAME FOR ALKYNE HAVING
madreJ [45]

Answer:

Ee your house 6r2f5r56rrrr6gjyf

Explanation:

4 0
2 years ago
What is the weight of dark matter​
Ostrovityanka [42]

Answer:

Knowing this, researchers from the University of Southern Denmark decided to investigate the size of these hypothetical hidden particles. According to the team, dark matter could weigh more than 10 billion billion (10^9) times more than a proton.

Explanation:

If this is true, a single dark matter particle could weigh about 1 microgram, which is about one-third the mass of a human cell (a typical human cell weighs about 3.5 micrograms), and right under the threshold for a particle to become a black hole.

3 0
3 years ago
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