The three of them increase from left to right across the periods of the periodic table, and at the same time, they decrease from up to down across the groups of the periodic table.

Ionization Energy is defined as the energy required to remove the atom of an electron.

Electron affinity is defined as the change in energy when electron is added to a negative ion.

Electronegativity is the ability of an atom to attract other atoms to itself.

7 0

3 years ago

Fill in the coefficients that was will balance the following reaction SnSO4 + KBr SnBr2 K2SO4

Juliette [100K]

The coefficients are 1 : 2 : 1 : 1

<u>Explanation:</u>

To be a balanced equation, the chemical equation should have has equal number of atoms on both reactant and product side.

Given chemical equation:

$a_{0} {SnSO}_{4}+a_{1} K B r \rightarrow a_{2} {SnBr}_{2}+a_{3} K_{2} S O_{4}$

Now, calculate the number of atoms present in reactant side:

Sn - 1

$S O_{4}$ - 1

K - 1

Br - 1

Then, calculate the number of atoms present in product side:

Sn - 1

$S O_{4}$ - 1

K - 2

Br - 2

Therefore, in order to balance this given chemical equation multiply KBr by 2 on reactant side. So, the balanced chemical equation is as follows.

$\Sn S O_{4}+2 K B r \rightarrow S n B r_{2}+K_{2} S O_{4}$

Hence,

$a_{0} - 1\\a_{1} - 2\\a_{2} - 1\\a_{3} - 1$

8 0

3 years ago

(15 points no links ) (also this is a serious question please excuse any somewhat offensive language)What are the specialized st

Irina18 [472]

the answer is C . GONADS.

3 0

3 years ago

Drag the correct symbol to the equation. Not all symbols will be used. A plutonium atom undergoes nuclear fission. Identify the

Naya [18.7K]

Answer:

$_{40}^{103}Zr$

Explanation:

For any nuclear equation, we should utilize the law of mass conservation and the law of charge conservation. The sum of the masses on the left-hand side of the arrow should be equal to the sum of the masses on the right-hand side of the arrow (those are the superscripts for each nucleus). Similarly, the sums of charges should be equal (this is the law of charge conservation).

Let's say that the missing species is X with a mass of 'M' and charge of 'Z':

$_{94}^{239}Pu+_0^1n\rightarrow _Z^MX+_{54}^{134}Xe+3_0^1n$