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2 years ago

1.05kg of aluminum what is the heat capacity ?

Chemistry

1 answer:

vitfil [10]2 years ago

8 0

The aluminum can with stand 0.942 J° C of heat

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If 200. mL of 0.60 M MgCl2(aq) is added to 400 mL of distilled water, what is the concentration of Mg and Cl in the resulting so

sladkih [1.3K]

Answer:

C. 0.20 M Mg ion & 0.40 M Cl ion

Explanation:

MgCl₂ is a ionic salt which is dissociated as this

MgCl₂ → Mg²⁺ + 2Cl⁻

First of all, we have a solution of 200 mL, with [MgCl₂] = 0.6M

Molarity . volume = moles.

0.6 mol/l . 0.2l = 0.12 mol

MgCl₂ → Mg²⁺ + 2Cl⁻

0.12mol 0.12 0.24

This moles are also in 400mL of water, so the new concentration is

[Mg²⁺] = 0.12 m/0.6L = 0.2M

[Cl⁻] = 0.24 m/0.6L = 0.4M

Remember we initially have 200mL and then, we add 400 mL, so we supose aditive volume. (600mL)

8 0

2 years ago

Describe how cells are organized into larger and larger groups to help living things survive

mestny [16]

Cells are organized into tissues. Tissues carry out specific functions. Groups of tissues can then form organs that also have specific functions to carry out. Lastly groups of organs form organ systems that regulate many functions in a specific part of the body.

3 0

2 years ago

A 0.216 g sample of carbon dioxide, CO2, has a volume of 507 mL and a pressure of 470 mmHg. What is the temperature of the gas i

Gala2k [10]

Answer:

The temperature of the gas is 876.69 Kelvin

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

P= 470 mmHg
V= 570 mL= 0.570 L
n= 0.216 g= 0.0049 moles (being the molar mass of carbon dioxide is 44 g/mole)

R= 62.36367 $\frac{mmHg*L}{mol*K}$

Replacing:

470 mmHg*0.570 L= 0.0049 moles* 62.36367 $\frac{mmHg*L}{mol*K}$ *T

Solving:

$T=\frac{470 mmHg*0.570 L}{0.0049 moles* 62.36367\frac{mmHg*L}{mol*K} }$

T= 876.69 K

The temperature of the gas is 876.69 Kelvin

6 0

2 years ago

What is the Relative Formula Mass of Potassium bromide?

Aleonysh [2.5K]

The relative formua for Potassium bromide is Kbr

6 0

2 years ago

24. H2SO4 has

Eddi Din [679]

Answer:

Explanation:

para sakin letter C ganonn

3 0

2 years ago