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LenaWriter [7]
2 years ago
15

What is the formula of sulfur diphosphide

Chemistry
2 answers:
Maslowich2 years ago
6 0

\huge \rm \ \blue \:{ \overbrace{ \underbrace{ \tt{ \color{red}{ \:  \:  \:  \:  \:  \:  answer \:  \:  \:  \:  \:  \: }}}}}

\huge \color{darkblue}P₂S_{5}

<h2><em>hope</em><em> it</em><em> helps</em></h2>

Wewaii [24]2 years ago
5 0

Answer:

P2S5

Explanation:

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Why is mercury the only metal to have been used in thermometers
MArishka [77]
I think because its the only one to be liquid  at  normal temperatures.
6 0
3 years ago
If 3.6 g of aluminum completely reacts, how much Al2O3 (in grams) can be produced
marissa [1.9K]

The amount in grams of  Al₂O₃ produced is approximately 6.80 g.

Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:

AL + O₂ → Al₂O₃

Let's balance it

4AL + 3O₂ → 2Al₂O₃

4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,

Since, aluminium reacts completely, it is the limiting reagent in the reaction. Therefore,

Atomic mass of AL = 27 g

Molar mass of  Al₂O₃ = 101.96 g/mol

4(27 g) of AL gives 2(101.96 g) of  Al₂O₃

3.6 g of AL will give ?

cross multiply

mass of  Al₂O₃ produced = 3.6 × 203.92 / 108   = 734.112 / 108 = 6.797

mass of  Al₂O₃ produced = 6.80 g.

read more: brainly.com/question/23982245?referrer=searchResults

8 0
3 years ago
Radioactive radium has a half-life of approximately 1,599 years. The initial quantity is 13 grams. How much (in grams) remains a
Luda [366]

The quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

<h3>What is half life period? </h3>

The time taken by substance to reduce to its half of its initial concentration is called half life period.

We will use the half- life equation N(t)

N e^{(-0.693t) /t½}

Where,

N is the initial sample

t½ is the half life time period of the substance

t2 is the time in years.

N(t) is the reminder quantity after t years .

Given

N = 13g

t = 350 years

t½ = 1599 years

By substituting all the value, we get

N(t) = 13e^(0.693 × 50) / (1599)

= 13e^(- 0.368386)

= 13 × 0.691

= 8.98

Thus, we calculated that the quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

learn more about half life period:

brainly.com/question/20309144

#SPJ4

4 0
1 year ago
What are the other types of particles that make up a water particle?​
Neko [114]

Answer:Well, if you mean atoms, it has 2 Hydrogen atoms and 1 Oxygen.

Explanation:Water is H20 therefore, it has 2 Hydrogen atoms and 1 Oxygen. Water isn't made up of particles, they are made of atoms.

3 0
3 years ago
Read 2 more answers
Find the molarity of 750 ml solution containing 346 g of potassium nitrate
Zinaida [17]
Given mass of KNO₃=346g
Molar mass of KNO₃=(39.098)+(14)+(15.99*3)=101.068gmol⁻¹
Volume of Solution=750ml=0.75dm³

Molarity=(mass of solute/molar mass of solute)*(1/volume of sol. in dm³)
            =(346/101.068)*(1/0.75)
            =4.56 mol dm⁻³
5 0
3 years ago
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