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zzz [600]
3 years ago
13

2. What is the Function of the Camshaft in an Internal Combustion Engine?

Engineering
1 answer:
mamaluj [8]3 years ago
8 0

Answer:

camshaft, in internal-combustion engines, rotating shaft with attached disks of irregular shape (the cams), which actuate the intake and exhaust valves of the cylinders.

Explanation:

I'm taking an engineering/tech class. I hope this helps! :)

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Answer:

whats the question

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6 0
2 years ago
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Refrigerant 134a enters an air conditioner compressor at 4 bar, 208C, and is compressed at steady state to 12 bar, 808C. The vol
SCORPION-xisa [38]

Answer:

heat transfer rate is -15.71 kW

Explanation:

given data

Initial pressure  = 4 bar

Final pressure  = 12 bar

volumetric flow rate = 4 m³ / min

work input to the compressor = 60 kJ per kg

solution

we use here super hated table for 4 bar and 20 degree temperature and 12 bar and 80 degree is

h1 = 262.96 kJ/kg

v1 = 0.05397 m³/kg

h2 = 310.24 kJ/kg

and here mass balance equation will be

m1  = m2

and mass flow equation is express as

m1 = \frac{A1\times V1}{v1}       .......................1

m1 = \frac{4\times \frac{1}{60}}{0.05397}  

m1 = 1.2353 kg/s

and here energy balance equation is express as

0 = Qcv - Wcv + m × [ ( h1-h2) + \frac{v1^2-v2^2}{2} + g (z1-z2) ]      ....................2

so here Qcv will be

Qcv =  m × [  \frac{Wcv}{m} + (h2-h1)  ]    ......................3

put here value and we get

Qcv =  1.2353 × [ {-60}+ (310.24-262.96) ]

Qcv =  -15.7130 kW

so here heat transfer rate is -15.71 kW

6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Jobisdone [24]

Answer:

Check image, right on PLATO

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3 years ago
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3 years ago
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A gas stream contains 18.0 mole% hexane and the remainder nitrogen. The stream flows to a condenser, where its temperature is re
NikAS [45]

Answer:

A. 72.53 mol/min

B. 76.2%

Explanation:

Please check attachment to see the diagram of the components I drew.

I first converted flow rate to a molar flow rate. I got 11.5mol/ min after converting. Check attachment

A.) When we create a balance on all these components

n1 + n2 + n3

n1 = n2 + 11.5

Creating a balance on hexane

n1y1C6H14 = n2y2C6H14 + n3y3C6H14

n1(0.18) = n2(0.05) + 11.5mol/min(1.00)

When we put the first equation into the second one:

(n2+11.5mol/min)0.18 + n2(0.05) + 11.5mol/min(1.00)

= 0.18n2 + 2.07min/mol = 0.5n2 + 11.5mol/min

Collect like terms

0.18n2 - 0.05n2 = 11.5 - 2.07min/mol

= 0.13n2 = 9.43

n2 = 9.43/0.13

n2 = 72.53 mol/min

72.53 is the flow rate of the gas stream leaving the burner.

B.) n1 = n2 + 11.5mol/min

n1 = 72.53mol/min + 11.5mol/min

n1 = 84.93mol/min

Amount of hexane entering condenser

n1c6H14 = y1C6H14 = 0.18(84.03mol/min)

= 15.1mol/min

The percentage condensed

= (11.5mol/min)/(15.1mol/min) * 100

= 76.2% of hexane is recovered as liquid

3 0
3 years ago
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