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2 years ago

When servicing piston rods and pins it is important to always

Engineering

2 answers:

11111nata11111 [884]2 years ago

5 0

Answer:

Pistons should be inspected and measured at several locations including the skirt, top, middle and bottom ring lands and the pin bore.

Explanation:

tatyana61 [14]2 years ago

3 0

Answer:

Pistons should be inspected and measured.

Explanation:

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The variation of the pressure of a fluid with density at constant temperature is known as the _____.

qaws [65]

The variation of the pressure of a fluid with density at constant temperature is known as the coefficient of compressibility.

<h3>What is a compressor?</h3>

A compressor can be defined as a mechanical device that is designed and developed to provide power to refrigerators, air conditioners, and other heating or cooling mechanical devices (engines), especially by increasing the pressure on air or other applicable gases.

In an isothermal process, the coefficient of compressibility is also known as isothermal compressibility or compressibility and it refers to a measure of the variation of the pressure and relative volume of a fluid with density at constant temperature.

Read more on coefficient of compressibility here: brainly.com/question/25237713

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2 years ago

A parallel circuit with two branches and an 18 volt battery. Resistor #1 on the first branch has a value of 220 ohms and resisto

likoan [24]

Answer:

2.455 W

Explanation:

The power dissipated in each branch is ...

P = V^2/R

So, the branch powers are ...

branch 1: 18^2/220 ≈ 1.473 W

branch 2: 18^2/330 ≈ 0.982 W

Total power is ...

1.473 W + 0.982 W = 2.455 W

8 0

3 years ago

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lions [1.4K]

Answer:

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3 years ago

For an Na+—Cl- ion pair, attractive and repulsive energies EA and ER, respectively, depend on the distance between the ions r, a

Lunna [17]

Answer:

Explanation:

$\text{The curve of the plot}$ $\mathbf{E_A,E_R, \ and \ E_N}$ $\text{can be seen in the attached diagram below}$

$\text{From the plot}$ , $\mathbf{r_o = 0.2 4nm \ and \ E_o =-5.3 eV}$

$\mathbf{We \ knew \ that: E_N = E_A + E_R}$

$\mathtt{GIven \ E_A = \dfrac{-1.436}{r}\ \ \ , E_R = \dfrac{7.32 \times 10^{-6}}{r^n} \ \ and \ \ n=8 }$

$\mathtt{Then; E_N = -\dfrac{-1.436}{r}+ \dfrac{7.32\times 10^{-6}}{r^8}}$

$\mathtt{Also; r_o = \Big( \dfrac{A}{nB} \Big)^{\dfrac{1}{1-n}}} \\ \\ \mathtt{ r_o = \Big( \dfrac{1.986}{8 \times 7.32\times 10^{-6}} \Big)^{\dfrac{1}{1-8}}} \\ \\ \mathbf{r_o = 0.236 nm}$

$E_o = \dfrac{-1.436}{\Big[\dfrac{1.436}{8(732\times 10^{-6})}\Big]^{\dfrac{1}{1-8}}} + \dfrac{7.32 \times 10^{-6}}{\Big[ \dfrac{1.436}{8\times7.32 \times 10^{-6} } \Big]^{\dfrac{8}{1-8}}}$