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3 years ago

((Psychology))According to Sternberg, consummate love includes:

2 answers:

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<span>According to Sternberg, consummate love includes:

This is the answer:

</span><span>B. intimacy, commitment, and passion
</span>
These three are the components of love in Sternberg's Triangular Theory of Love.

Hope this helps.

Pepsi [2]3 years ago

5 0

Answer:

The correct answer is B. According to Sternberg, consummate love includes intimacy, commitment, and passion.

Explanation:

The triangular love theory of the American psychologist Robert Sternberg characterizes love in an interpersonal relationship according to three different components, which are intimacy, passion and commitment:

-Intimacy, understood as those feelings within a relationship that promote the approach, the link, the connection and mainly the self-revelation. Or in other words, the affection towards another person that arises from feelings of closeness, affective bond and relationship, implies the desire to give, to receive, to share, and so on.

-Passion, as a state of intense desire for union with the other, as an expression of desires and needs, great sexual or romantic desire accompanied by psychological excitement.

-Commitment, the decision to love another person and the commitment to maintain that love. This component implies maintaining the relationship in good times and bad times

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2.4 physics assignment.

kvv77 [185]

Answer:The distance o the ramp that the car traveled is given by d=(1/2)at^2=(0.5)(3.96)(5.76)^2=65.69 meters. The horizontal component of this travel is 65.69*

Explanation:

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2 years ago

A ball is dropped from rest from the top of a building of height h. At the same instant, a second ball is projected vertically u

uranmaximum [27]

Answer:

a) $t = \sqrt{\frac{h}{2g}}$

b) Ball 1 has a greater speed than ball 2 when they are passing.

c) The height is the same for both balls = 3h/4.

Explanation:

a) We can find the time when the two balls meet by equating the distances as follows:

$y = y_{0_{1}} + v_{0_{1}}t - \frac{1}{2}gt^{2}$

Where:

$y_{0_{1}}$ : is the initial height = h

$v_{0_{1}}$ : is the initial speed of ball 1 = 0 (it is dropped from rest)

$y = h - \frac{1}{2}gt^{2}$ (1)

Now, for ball 2 we have:

$y = y_{0_{2}} + v_{0_{2}}t - \frac{1}{2}gt^{2}$

Where:

$y_{0_{2}}$ : is the initial height of ball 2 = 0

$y = v_{0_{2}}t - \frac{1}{2}gt^{2}$ (2)

By equating equation (1) and (2) we have:

$h - \frac{1}{2}gt^{2} = v_{0_{2}}t - \frac{1}{2}gt^{2}$

$t=\frac{h}{v_{0_{2}}}$

Where the initial velocity of the ball 2 is:

$v_{f_{2}}^{2} = v_{0_{2}}^{2} - 2gh$

Since $v_{f_{2}}^{2}$ = 0 at the maximum height (h):

$v_{0_{2}} = \sqrt{2gh}$

Hence, the time when they pass each other is:

$t = \frac{h}{\sqrt{2gh}} = \sqrt{\frac{h}{2g}}$

b) When they are passing the speed of each one is:

For ball 1:

$v_{f_{1}} = - gt = -g*\sqrt{\frac{h}{2g}} = - 0.71\sqrt{gh}$

The minus sign is because ball 1 is going down.

For ball 2:

$v_{f_{2}} = v_{0_{2}} - gt = \sqrt{2gh} - g*\sqrt{\frac{h}{2g}} = (\sqrt{1} - \frac{1}{\sqrt{2}})*\sqrt{gh} = 0.41\sqrt{gh}$

Therefore, taking the magnitude of ball 1 we can see that it has a greater speed than ball 2 when they are passing.

c) The height of the ball is:

For ball 1:

$y_{1} = h - \frac{1}{2}gt^{2} = h - \frac{1}{2}g(\sqrt{\frac{h}{2g}})^{2} = \frac{3}{4}h$

For ball 2:

$y_{2} = v_{0_{2}}t - \frac{1}{2}gt^{2} = \sqrt{2gh}*\sqrt{\frac{h}{2g}} - \frac{1}{2}g(\sqrt{\frac{h}{2g}})^{2} = \frac{3}{4}h$

Then, when they are passing the height is the same for both = 3h/4.

I hope it helps you!

7 0

3 years ago

A 4000kg truck has a head-on inelastic collision with a 2500kg truck.

iogann1982 [59]

Answer:it could be B

Explanation:

im not sure

7 0

3 years ago

Convection is the type of heat transfer that occurs in which of the following?

katrin [286]

C

Tfsdghjjjjjhvv (Ignore)

5 0

3 years ago

a minute later the green car is traveling 60 miles per hour north, the blue car traveling 60 miles per hour south how is the gre

Zanzabum

Answer:

A) The green cars's velocity has the same magnitude as the blue car's velocity.

B) the difference about their velocity is the direction of the velocity which is 180° in the opposite directions.

Explanation:

Velocity is a vector quantity that has both magnitude and direction. The magnitude shows the size, and the direction shows the path the motion takes.

Both cars have the same magnitude but different directions. The difference in their direction is at a 180°angle.

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3 years ago