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3 years ago

((Psychology))According to Sternberg, consummate love includes:

2 answers:

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<span>According to Sternberg, consummate love includes:

This is the answer:

</span><span>B. intimacy, commitment, and passion
</span>
These three are the components of love in Sternberg's Triangular Theory of Love.

Hope this helps.

Pepsi [2]3 years ago

5 0

Answer:

The correct answer is B. According to Sternberg, consummate love includes intimacy, commitment, and passion.

Explanation:

The triangular love theory of the American psychologist Robert Sternberg characterizes love in an interpersonal relationship according to three different components, which are intimacy, passion and commitment:

-Intimacy, understood as those feelings within a relationship that promote the approach, the link, the connection and mainly the self-revelation. Or in other words, the affection towards another person that arises from feelings of closeness, affective bond and relationship, implies the desire to give, to receive, to share, and so on.

-Passion, as a state of intense desire for union with the other, as an expression of desires and needs, great sexual or romantic desire accompanied by psychological excitement.

-Commitment, the decision to love another person and the commitment to maintain that love. This component implies maintaining the relationship in good times and bad times

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The magnitude of the electric field at the proton's location is 10,437.5 N/C.

<h3>What the magnitude of the electric field?</h3>

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2 years ago

An object is moving at a constant velocity of 10 m/s for 5 seconds. What is

german

initial velocity (u)=0m/s

final velocity (v)=10m/s

time( t)=5s

acceleration (a)=v-u÷t

acceleration (a)=10-0÷5

acceleration (a)=10÷5

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3 years ago

A rock falls from rest off a cliff and hits the ground in 2 seconds. If there is no air resistance, determine the rock's velocit

mihalych1998 [28]

Answer:

19.6m/s

Explanation:

A Rock falling off a cliff can be modeled as an object starting with zero velocity moves with constant acceleration for certain period of time, for such motion following equation of motion can be used.

$v(t) = v_{0} +at$

here in our case $v_{0} =0$ because object starts off from rest and $a = g =9.8m/s^2$ is acceleration because of gravity ( Motion under gravity).

and of course t = 2 second.

Now by substituting all this information in equation of motion we get.

$v(2s) = 0+9.8m/s^2 *2s = 19.6m/s$

that would be the velocity of rock as it would hit the ground.

Note! We have assumed that there is no air resistance.

A rock falling off a cliff can be modeled as an object starting with zero velocity moves with constant acceleration for a certain period of time, for such motion following equation of motion can be used.

here in our case because object starts off from rest and is acceleration because of gravity ( Motion under gravity).

and of course t = 2 seconds.

Now by substituting all this information in equation of motion we get.

V = 19.6m/s

that would be the velocity of rock as it would hit the ground.

Note! We have assumed that there is no air resistance.

5 0

3 years ago

A 24.0 cm long screwdriver is used as a lever to open a can of paint. If the fulcrum is 0.500 cm away from the end of the screwd

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The ideal mechanical advantage of the screwdriver is 47

Explanation: