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valentinak56 [21]
3 years ago
7

((Psychology))According to Sternberg, consummate love includes:

Physics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0
<span>According to Sternberg, consummate love includes:

This is the answer:

</span><span>B. intimacy, commitment, and passion
</span>
These three are the components of love in Sternberg's Triangular Theory of Love.

Hope this helps.
Pepsi [2]3 years ago
5 0

Answer:

The correct answer is B. According to Sternberg, consummate love includes intimacy, commitment, and passion.

Explanation:

The triangular love theory of the American psychologist Robert Sternberg characterizes love in an interpersonal relationship according to three different components, which are intimacy, passion and commitment:

-Intimacy, understood as those feelings within a relationship that promote the approach, the link, the connection and mainly the self-revelation. Or in other words, the affection towards another person that arises from feelings of closeness, affective bond and relationship, implies the desire to give, to receive, to share, and so on.

-Passion, as a state of intense desire for union with the other, as an expression of desires and needs, great sexual or romantic desire accompanied by psychological excitement.

-Commitment, the decision to love another person and the commitment to maintain that love. This component implies maintaining the relationship in good times and bad times

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Find the current that flows in a silicon bar of 10-μm length having a 5-μm × 4-μm cross-section and having free-electron and hol
klasskru [66]

The current flowing in silicon bar is 2.02 \times 10^-12 A.

<u>Explanation:</u>

Length of silicon bar, l = 10 μm = 0.001 cm

Free electron density, Ne = 104 cm^3

Hole density, Nh = 1016 cm^3

μn = 1200 cm^2 / V s

μр = 500 cm^2 / V s

The total current flowing in the bar is the sum of the drift current due to the hole and the electrons.

J = Je + Jh

J = n qE μn + p qE μp

where, n and p are electron and hole densities.

J = Eq (n μn + p μp)

we know that E = V / l

So, J = (V / l) q (n μn + p μp)

     J = (1.6 \times 10^-19) / 0.001 (104 \times 1200 + 1016 \times 500)

     J = 1012480 \times 10^-16 A / m^2.

or

J = 1.01 \times 10^-9 A / m^2

Current, I = JA

A is the area of bar, A = 20 μm = 0.002 cm

I = 1.01 \times 10^-9 \times 0.002 = 2.02 \times 10^-12

So, the current flowing in silicon bar is 2.02 \times 10^-12 A.  

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