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2 years ago

((Psychology))According to Sternberg, consummate love includes:

2 answers:

7 0

According to Sternberg, consummate love includes:

This is the answer:

B. intimacy, commitment, and passion

These three are the components of love in Sternberg's Triangular Theory of Love.

Hope this helps.

Pepsi [2]2 years ago

5 0

Answer:

The correct answer is B. According to Sternberg, consummate love includes intimacy, commitment, and passion.

Explanation:

The triangular love theory of the American psychologist Robert Sternberg characterizes love in an interpersonal relationship according to three different components, which are intimacy, passion and commitment:

-Intimacy, understood as those feelings within a relationship that promote the approach, the link, the connection and mainly the self-revelation. Or in other words, the affection towards another person that arises from feelings of closeness, affective bond and relationship, implies the desire to give, to receive, to share, and so on.

-Passion, as a state of intense desire for union with the other, as an expression of desires and needs, great sexual or romantic desire accompanied by psychological excitement.

-Commitment, the decision to love another person and the commitment to maintain that love. This component implies maintaining the relationship in good times and bad times

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See the diagram above. Which of the following is the best prediction of what would happen if you increased the distance in secti

Inessa [10]

By the definition of wavelength, the answer is the letter D, the wavelength would decrease.

We can see in the diagram a wave motion.

A wave has some characteristics:

Has an amplitude, the distance from 0 to the crest (highest point in the y-direction, point (3) in the figure) it would see in the figure as (2)
Has wavelength, the distance between the crests.
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Now, if we increase the distance of the crests, by the definition shown above, we will increase the wavelength.

Therefore, the answer is letter D, the wavelength would increase.

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3 years ago

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2 years ago

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Suppose that a person gets hit by a bus moving at 30 mi/h with a 58,000 lbs of force in the direction of motion. If the mass of

alexandr402 [8]

The impulse of a force is due to the change in the motion of an object

A. The persons speed after impact is approximately 59.38 mi/h

B. The expected speed is 29.89 mi/h which is less than the findings

Reason:

Known parameters are;

The speed of the bus, v = 30 mi/h

The force with which the person was hit, F = 58,000 lbs

Mass of the bus, M = 40,000 lbs

Mass of the person, m = 150 lbs

Duration of the impact, Δt = 0.007 seconds

A. The speed of the person at the end of the impact, v, is given as follows;

The impulse of the force = F × Δt = m × Δv

For the person, we get;

58,000 lbf ≈ 1866094.816 lb·ft./s²

58,000 lbf × 0.007 s = 150 lbs × Δv

1,866,094.816 lb·ft./s²

$\Delta v = \dfrac{1,866,094.816\ lbs \times 0.007 \, s}{150 \, lbs} \approx 87.084 \ ft./s$

Δv = v₂ - v₁

The initial speed of the person at the instant, can be as v₁ = 0

The final speed, v₂ = Δv - v₁

∴ v₂ ≈ 87.084 ft./s - 0 = 87.084 ft./s

≈ 87.084 ft./s

$v_2 \approx \dfrac{87.084 \ ft./s}{y} \times\dfrac{1 \ mi}{5280 \ ft.} \times \dfrac{3,600 \ s}{1 \, hour} \approx 59.38 \ mi/h$

The speed of the person at the end of the impact, v₂ ≈ 59.38 mi/h

B. Where the momentum is conserved, we have;

m₁·v₁ + m₂v₂ = (m₁ + m₂)·v

$v = \dfrac{m_1 \cdot v_1 + m_2 \cdot v_2}{m_2 + m_1}$

$v = \dfrac{40,000 \times 30 + 150 \times 0}{40,000 + 150} \approx 29.89$

The expected speed of the person at the end of the impact is 29.89 mi/h, and therefore, the findings does not agree with the expectation

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2 years ago

According to the first rule, if a force pulls on one end of a rope, the tension in the rope equals the magnitude of the pulling

mixer [17]

Answer:

Explanation:

Here in the question the mass of the pulley is zero, hence, the tension in the cable throughout is same.

magnitude of tension in rope 1 is

T1= F

Hence the tension T1 is rope 1 is F.

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3 years ago

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