1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liono4ka [1.6K]
3 years ago
7

Breanna is standing beside a merry-go-round pushing 19° from the tangential direction and is able to accelerate the ride and her

friends from rest to a frequency of 10 rpm in 9 seconds. Assume the merry-go-round is a uniform disc of radius 2.3 m and has a mass of 750 kg. Rachel (48 kg) and Tayler (46 kg) sit opposite each other on the edge of the ride. What force did Elizabeth push with? (N) (include units with answer) How much work did Elizabeth do? (J) (include units with answer)
Physics
1 answer:
Nastasia [14]3 years ago
5 0

Answer

given,

angle of pushing =19°

frequency = 10 rpm

time = 9 sec

radius of disk = 2.3 m

mass of merry-go-round = 750 Kg

Rachel mass = m₁ = 48 Kg

Tayler mass = m₂ = 46 Kg

moment of inertial

I = \dfrac{1}{2}Mr^2 + (m_1+m_2) r^2

I = \dfrac{1}{2}\times 750 \times 2.3^2 + (48+46) 2.3^2

I = 2481.01 Kg.m²

ω = 10 rpm = 10 \times \dfrac{2\pi}{60}

ω = 1.05 rad/s

ω₀ = 0

\alpha= \dfrac{\omega-\omega_0}{t}

\alpha= \dfrac{1.05-0}{9}

α = 0.117 rad/s²

we know,

T = I α

F cos 16° = 2481.01 x 0.117

F = 301.98 N

Work done =

=\dfrac{1}{2}I\omega^2

=\dfrac{1}{2}\times 2481.01\times 1.05^2

W =1367.66 J

You might be interested in
A 0.500 kg ball is dropped from rest at a point 1.20 m above the floor. The ball rebounds straight upward to a height of 0.700 m
KatRina [158]

To solve this problem we will apply the concepts related to energy conservation. With this we will find the speed before the impact. Through the kinematic equations of linear motion we will find the velocity after the impact.

Since the momentum is given as the product between mass and velocity difference, we will proceed with the velocities found to calculate it.

Part A) Conservation of the energy

mgh = \frac{1}{2} mv^2

v_1 = \sqrt{2gh}

v_1 = \sqrt{2(9.8)(1.20)}

v_1 = 4.84m/s

\therefore v_1 = -4.84/s \rightarrow \text{Negative direction downward}

Part B)  Kinematic equation of linear motion,

v_2^2 = u_0^2 +2a\Delta y

Here

v= 0 Because at 1.5m reaches highest point, so v=0

0 = u_2^2 +2(-9.8)(0.7)

u_2 = 3.7m/s

Therefore the velocity after the collision with the floor is 3.7m/s

PART C) Total change of impulse is given as,

J = P_2 -P_1

J = mU_2-mV_1

J = m(U_2-V_1)

J = (0.5)(3.7-(-4.84))

J = 4.27kg \cdot m/s \rightarrow \text{Upward because is positive}

6 0
4 years ago
The electric motor of a model train accelerates the train from rest to 0.685 m/s in 21.5 ms. The total mass of the train is 875
Natali [406]

Answer:

P=9.58 W

Explanation:

According to Newton's second law, and assuming friction force as zero:

F_m=m.a\\F_m=0.875kg*a

The acceleration is given by:

a=\frac{\Delta v}{t}\\a=\frac{0.685m/s}{21.5*10^{-3}s}\\\\a=31.9m/s^2

So the force exerted  by the motor is:

F_m=0.875kg*31.9m/s^2\\F_m=27.9N

The work done by the motor is given by:

W_m=F_m*d\\\\d=\frac{1}{2}*a*t^2\\d=\frac{1}{2}*31.9m/s^2*(21.5*10^{-3}s)^2\\\\d=7.37*10^{-3}m

W_m=27.9N*7.37*10^{-3}m\\W_m=0.206J

And finally, the power is given by:

P=\frac{W_m}{t}\\P=\frac{0.206J}{21.5*10^{-3}s}\\\\P=9.58W

8 0
3 years ago
Which speed(s) is/are below the sound barrier in air? A. 257 m/s B. 1,030 m/s C. 10 m/s
Assoli18 [71]

The answers are A&C. please mark me brainliest

8 0
3 years ago
Calculate the change in internal energy (ΔE) for a system that is giving off 25.0 kJ of heat and is changing from 12.00 L to 6.0
Alexxandr [17]

Explanation:

The given data is as follows.

         q = -25.0 kJ,     Pressure (P) = 1.50 atm

   \Delta V = (12 - 6) L = 6 L

Therefore, product of pressure and change in volume will be as follows.

             P \Delta V = 1.50 atm \times 6 L

                                = 7.5 L atm

                                = 7.5 \times 101.3

                                = 759.75 J

Now, we will calculate the change in internal energy as follows.

                   \Delta E = q + w

                                = q + P \Delta V

                                = -25000 kJ + 759.75 J

                                 = 24240.25 J

or,                              = 24.240 kJ      (as 1 kJ = 1000 J)

Thus, we can conclude that the change in internal energy (\Delta E) for a system is 24.240 kJ.

7 0
4 years ago
Which of the following is an ionic compound?
const2013 [10]

compound is covalent! The bond between HI is a polar covalent bond. ... It is because Hydrogen is electropositive in nature in comparison to Iodine.

7 0
3 years ago
Other questions:
  • __________ is not included in your perception time.
    11·2 answers
  • Neptune (currently the most distant planet from the Sun!) lies about 4.5x109 kilometers from the Earth. If you were traveling to
    8·1 answer
  • Explain why the feet of camels and wadding birds have the shapes that they have.
    13·1 answer
  • Which of the following is not an example of an abiotic factor? a. plants b. air c. temperature d. soil Please select the best an
    7·2 answers
  • which of the following statements best reflects the symbolic-interaction approach to the study of aging? A. Perception of aging
    13·2 answers
  • Explain Newton's third law in your own words.
    15·2 answers
  • A straight wire carries a current of 238 mA from right to left. What is the magnetic field at a point 10.0 cm directly below the
    13·1 answer
  • A ray of light passes from air into a block of clear plastic. How does the angle of incidence in the air compare to the angle of
    11·1 answer
  • How can the conductivity of a semiconductor be increased?
    15·1 answer
  • Which diagram best represents a convex lens?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!