Given:
I = 30dB
P = 66 × Pa
Solution:
Formula used:
I = (1)
where,
I = intensity of sound
P = absolute pressure
= reference pressure
Using Eqn (1), we get:
=
= 2.08 ×
Pa
A brick is dropped from rest from the top of a building through air (air resistance is present) to the ground below. how does th
1 answer:
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The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
The force applied to an object increases with increases in the velocity of the object.
In the given diagram, the resultant velocity of the puck is calculated as follows;
Figure a:
Figure b:
Figure c:
Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
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To solve this problem we will apply the concept related to the amplitude and the Doppler effect. The difference between the maximum and minimum frequency detected by the microphone would be given by the mathematical function
Here,
= Source Frequency
= Speed of microphone
v = Speed sound
Maximum speed of the microphone is
Now the amplitude is
Here T means the Period, then
A= 0.2605m
Therefore the amplitude of the simple harmonic motion is 0.2605m