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2 years ago

13

Nowkwkskkdmdkdkeekdjsjskskwkwkwkwowowowo

2 answers:

Anvisha [2.4K]2 years ago

6 0

Answer:

Dude, that's exactly how I feel!

Zarrin [17]2 years ago

4 0

Answer:

I think the answer is jdndksjbxjxkxnxndkxkxn I'm not sure tho

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What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough

olga55 [171]

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

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1 year ago

Why is it important for someone to hold enzymes in their functional shapes

kumpel [21]

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there are spaces within the enzymes that is active. That active site allows substrates to join in. This helps the enzyme carry out the chemical reaction with the substrate.

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3 years ago

Which of the following statements about alkenes is not correct?

professor190 [17]

<span>Option-C: They react mainly by substitution.

Explanation:
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2 years ago

2CO + O2 → 2002

Reika [66]

Answer:

B: Increasing the volume inside the reaction chamber

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2 years ago

If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution

Shtirlitz [24]

Explanation:

a) Using Beer-Lambert's law :

Formula used :

$A=\epsilon \times c\times l$

where,

A = absorbance of solution = 0.945

c = concentration of solution = ?

l = length of the cell = 1.20 cm

$\epsilon$ = molar absorptivity of this solution = $5.56\times 10^4 M^{-1} cm^{-1}$

$0.945=5.56\times 10^4 M^{-1} cm^{-1}\times 1.20 \times c$

$c=1.4163\times 10^{-5} M=14.16 \mu M$

( $1\mu M=10^{-6} M$ )

14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.

b) $c=1.4163\times 10^{-5} mol/L$

1 L of solution contains $1.4163\times 10^{-5}$ moles of red dye.

Mass of $1.4163\times 10^{-5}$ moles of red dye:

$1.4163\times 10^{-5}\times 879.86g/mol=0.01246 g$

$(w/v)\%=\frac{\text{Mass of solute (g)}}{\text{Volume of solvent (mL)}}\times 100$

$red(w/v)\%=\frac{0.01246 g}{1000 mL}\times 100=0.001246\%$

c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = $c=1.4163\times 10^{-5} M$

Concentration of red solution after dilution = c'

$c=c'\times 5$

$1.4163\times 10^{-5} M=c'\times 5$

$c'=2.83\times 10^{-6} M$

The final concentration of the diluted solution is $2.83\times 10^{-6} M$

8 0

2 years ago