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Lorico [155]
4 years ago
12

Which is not a descriptor or tactic used by abusers?

Chemistry
1 answer:
attashe74 [19]4 years ago
4 0
It should be B. All of the other choices are used often by abusers
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At Christmas time, I like to burn scented candles that smell like sugar cookies. How does the candle in one location change the
LekaFEV [45]

Answer:

its called diffusion

Explanation:

so the air is a substance and then it mixes with another substance which is the scent of the candle then the particles mix together to make a mixture

3 0
2 years ago
In a lead-acid battery, the electrodes are consumed. In this battery, Select one: a. the anode is PbO2. b. the cathode is Pb. c.
Gnoma [55]

Answer:

The correct answer is option e.

Explanation:

The lead acid battery consists lead as an anode and lead oxide as a cathode. Both the electrodes are suspended in dilute sulfuric acid which act as an electrolyte.

At anode: Oxidation

Pb(s)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)+2e^-

At cathode: Reduction

PbO_2+SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow PbSO_4(s)+2H_2O

6 0
3 years ago
Please answer in details. what class of carbon is coal ​
klio [65]
Coal falls under Graphite
4 0
3 years ago
Determine el PH y el % de disociación de una solución de ácido débil, sabiendo que se disuelven 20 gramos del ácido (masa molar=
IceJOKER [234]

Answer:

pH = 4.27. Porcentaje de disociación: 0.03%

Explanation:

El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

Donde la constante de equilibrio, Ka, es

Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]

Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:

[H⁺] = [X⁻]

[HX] es:

20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M

Reemplazando es Ka:

1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]

2.858x10⁻⁹ = [H⁺]²

5.35x10⁻⁵M = [H⁺]

pH = -log[H⁺]

<h3>pH = 4.27</h3>

El porcentaje de disociacion es [X⁻] / [HX] inicial * 100

Reemplazando

5.35x10⁻⁵M / 0.1732M * 100

<h3>0.03%</h3>
5 0
3 years ago
Given the following reaction: NH4SH (s) &lt;--&gt; NH3 (g) + H2S (g) If we start
almond37 [142]

Answer:

D. 0.3 M

Explanation:

                                              NH4SH (s)      <-->            NH3 (g) + H2S (g)

Initial concentration              0.085mol/0.25L             0                 0

Change in concentration     -0.2M                               +0.2 M        +0.2M

Equilibrium               0.035mol/0.25 L=0.14M             0.2M           0.2M

concentration

Change in concentration (NH4SH) = (0.085-0.035)mol/0.25L =0.2M

K = [NH3]*[H2S]/[NH4SH] = 0.2M*0.2M/0.14M ≈ 0.29 M ≈ 0.3M

4 0
3 years ago
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