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MaRussiya [10]
3 years ago
7

Suppose the amu had been defined as 110th of the mass of a phosphorus atom. What would be the relative mass of carbon-12?

Chemistry
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

The relative mass of carbon would be A_{r,C}  = \frac{12}{0.282}=42.62\, amu

Explanation:

The amu is defined as 1/12 of the mass of a ^{12}C atom, thus according to the definition, the relative mass of carbon is exactly 12. If the definition of the AMU changed, we could calculate what the new relative mass is by dividing the relative mass of ^{12}C  by the mass of the new AMU in old AMUs.

The atomic weight of Phosphorus is 30.973, therefore  an amu would be \frac{30.973}{110}=0.282  in old AMUs, if the atomic weight of carbon is 12.00, then in the new amu:

A_{r,C}  = \frac{12}{0.282}=42.62\, amu

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so how many moles of Fe are in 3.10 mole of iron oxide FeO still waiting for answer please, my grandchild needs help that I can'
alisha [4.7K]
The answer is 3.10 because it's still the same amount moles of iron.
7 0
3 years ago
At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L . What volume wo
Nostrana [21]

Taking into account the Charles's law, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.

<h3>Charles's Law</h3>

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, at a constant pressure.

Volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles's law is a law that says that the quotient that exists between the volume and the temperature will always have the same value:

V÷ T= k

Considering an initial state 1 and a final state 2, it is satisfied:

V1÷ T1= V2÷ T2

<h3>Volume at 65°C</h3>

In this case, you know:

  • V1= 22.4 L
  • T1= 0 C= 273 K
  • V2= ?
  • T2= 65 C= 338 K

Replacing in Charles's law:

22.4 L÷ 273 K= V2÷ 338 K

Solving:

(22.4 L÷ 273 K) ×338 K= V2

<u><em>V2= 27.73 L</em></u>

Finally, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.

Learn more about Charles's law:

brainly.com/question/4147359

#SPJ1

3 0
1 year ago
I NEED HELP ASAP!!!
Rus_ich [418]

Explanation:

To answer this question, we'll need to use the Ideal Gas Law:

p

V

=

n

R

T

,

where

p

is pressure,

V

is volume,

n

is the number of moles

R

is the gas constant, and

T

is temperature in Kelvin.

The question already gives us the values for

p

and

T

, because helium is at STP. This means that temperature is

273.15 K

and pressure is

1 atm

.

We also already know the gas constant. In our case, we'll use the value of

0.08206 L atm/K mol

since these units fit the units of our given values the best.

We can find the value for

n

by dividing the mass of helium gas by its molar mass:

n

=

number of moles

=

mass of sample

molar mass

=

6.00 g

4.00 g/mol

=

1.50 mol

Now, we can just plug all of these values in and solve for

V

:

p

V

=

n

R

T

V

=

n

R

T

p

=

1.50 mol

×

0.08206 L atm/K mol

×

273.15 K

1 atm

= 33.6 L

this is not the answer but it will help you

do by the formula it is on the answer

3 0
2 years ago
Help would be majorly appreciated
Sophie [7]

Answer:

a) the atomic number is 15

b) the mass number is 15+16 = 31

c) element is phosphorus

d)Group 15 period 3

6 0
2 years ago
Determine the rate of a reaction that follows the rate law:
Natali5045456 [20]
A. 0.12 (mol/L)/s

rate = 1 x 10-2 • 2^2 • 3
8 0
3 years ago
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