The answer is 3.10 because it's still the same amount moles of iron.
Taking into account the Charles's law, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.
<h3>Charles's Law</h3>
Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, at a constant pressure.
Volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles's law is a law that says that the quotient that exists between the volume and the temperature will always have the same value:
V÷ T= k
Considering an initial state 1 and a final state 2, it is satisfied:
V1÷ T1= V2÷ T2
<h3>Volume at 65°C</h3>
In this case, you know:
- V1= 22.4 L
- T1= 0 C= 273 K
- V2= ?
- T2= 65 C= 338 K
Replacing in Charles's law:
22.4 L÷ 273 K= V2÷ 338 K
Solving:
(22.4 L÷ 273 K) ×338 K= V2
<u><em>V2= 27.73 L</em></u>
Finally, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.
Learn more about Charles's law:
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Explanation:
To answer this question, we'll need to use the Ideal Gas Law:
p
V
=
n
R
T
,
where
p
is pressure,
V
is volume,
n
is the number of moles
R
is the gas constant, and
T
is temperature in Kelvin.
The question already gives us the values for
p
and
T
, because helium is at STP. This means that temperature is
273.15 K
and pressure is
1 atm
.
We also already know the gas constant. In our case, we'll use the value of
0.08206 L atm/K mol
since these units fit the units of our given values the best.
We can find the value for
n
by dividing the mass of helium gas by its molar mass:
n
=
number of moles
=
mass of sample
molar mass
=
6.00 g
4.00 g/mol
=
1.50 mol
Now, we can just plug all of these values in and solve for
V
:
p
V
=
n
R
T
V
=
n
R
T
p
=
1.50 mol
×
0.08206 L atm/K mol
×
273.15 K
1 atm
= 33.6 L
this is not the answer but it will help you
do by the formula it is on the answer
Answer:
a) the atomic number is 15
b) the mass number is 15+16 = 31
c) element is phosphorus
d)Group 15 period 3
A. 0.12 (mol/L)/s
rate = 1 x 10-2 • 2^2 • 3