Answer:
98.6%
Explanation:
First we put down the equation representing the decomposition of sodium bicarbonate.
2NaHCO3(s) ----> Na2CO3(s) + H2O(l) + CO2(g)
We can see from the data provided that the mass of sodium bicarbonate reacted is 3.01 g.
The number of moles of sodium bicarbonate reacted= mass of sodium bicarbonate/ molar mass of sodium bicarbonate
Molar mass of sodium bicarbonate= 84.007 g/mol
Number of moles of sodium bicarbonate=3.01 g/ 84.007 g/mol
Number of moles of sodium bicarbonate= 0.0358 moles
From the balanced reaction equation,
2 moles of sodium bicarbonate yields 1 mole of sodium carbonate
Hence 0.0358 moles of sodium bicarbonate yields 0.0358/2 = 0.0179 moles of sodium carbonate
Theoretical yield of sodium carbonate = number of moles of sodium carbonate × molar mass of sodium carbonate
Molar mass of sodium carbonate= 105.9888 g/mol
Theoretical yield of sodium carbonate= 0.0179 moles × 105.9888 g/mol
Theoretical yield of sodium carbonate= 1.897 g
Actual yield of sodium carbonate= 1.87 g
%yield of sodium carbonate= 1.87/1.897 ×100
%yield of sodium carbonate= 98.6%
