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GenaCL600 [577]
3 years ago
15

Who developed the orbital model of the atom?

Chemistry
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

Ernest Rutherford

Explanation:

that's I think

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What is the density of a bar of lead that weighs 173 g and has the following dimensions: l= 2.00 cm, w = 3.00 cm, h = 1.00 in?
oksano4ka [1.4K]

Answer:

\rho=7373.2g/cm^3

Explanation:

Hello!

In this case, since the density is defined as the degree of compactness of a substance, and is defined as the mass over the volume:

\rho= \frac{m}{V}

Given the dimensions of the bar of lead, we can compute the volume as shown below:

V=2.00cm*3.00cm*1.00in*\frac{1in}{2.54cm} \\\\V=2.36cm^3

Thus, the density turns out:

\rho=\frac{173g}{2.36cm^3} \\\\\rho=7373.2g/cm^3

Best regards!

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Given that oxygen has an atomic number of 8.
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