<u>We are given:</u>
V1 = 100 mL P1 = 6 atm
V2 = x mL P2 = 1 atm
<u>Solving for 'x' : </u>
According to the Boyle's law:
P ∝ 1/V (pressure and volume are inversely proportional)
PV = k (where k is a constant)
since the constant k will be the same:
P1V1 = P2V2
replacing the variables
6 * 100 = 1 * x
x = 600 mL OR 0.6L
Therefore, the gas will have a volume of 600mL or 0.6L
It will spread out making the sound travel faster then it usually does in the air(i think) let me know if you need help with anything else
