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1 year ago

Which of the following statements about the periodic table is true?

Physics

1 answer:

skelet666 [1.2K]1 year ago

3 0

Answer:

elements are the same columns are similar in there property

Explanation:

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Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.2589 N when separated by

Harlamova29_29 [7]

Answer:

$q_1 = 7.19 \times 10^{-6} C$

$q_2 = -1.0 \times 10^{-6} C$

Explanation:

Let the initial charge on the two spheres are

$q_1, -q_2$

now we know that the force between them is given as

$F = \frac{kq_1q_2}{r^2}$

$0.2589 = \frac{kq_1q_2}{0.5^2}$

$q_1q_2 = 7.19 \times 10^{-12}$

now when two spheres are connected then final charge on them is given as

$q = \frac{q_1 - q_2}{2}$

now the force between them is given as

$0.3456 = \frac{k(q_1 - q_2)^2}{4(0.5)^2}$

now we have

$q_1 - q_2 = 6.19 \times 10^{-6}$

So by solving above two equations we have

$q_1 = 7.19 \times 10^{-6} C$

$q_2 = -1.0 \times 10^{-6} C$

3 0

2 years ago

Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a −3.0-μC charge

Naddik [55]

Answer:

4.30 x 10⁵ N/C

Explanation:

Two positive +3.0-μC point charges at opposite corners of the square creates equal and opposite electric field at the center. hence the electric field by these two positive charges at opposite corners becomes zero.

$a$ = length of the square of side = 0.50 m

$r$ = distance of the center from each corner = $\frac{a}{sqrt(2)} = \frac{0.50}{sqrt(2)} = 0.354 m$

Magnitude of net electric field at the center is given as

$E = \frac{2kq}{r^{2}} \\E = \frac{2(8.99\times10^{9})(3\times10^{-6})}{(0.354)^{2}} \\E = 4.30\times10^{5} NC^{-1}$

6 0

2 years ago

A stone is thrown straight up from the edge of a roof, 925 feet above the ground, at a speed of 20 feet per second. Remembering

Black_prince [1.1K]

<h2>Answer: 469 feet</h2>

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y$ is the height of the stone at 6s (the value we want to find)

$y_{o}=925ft$ is the initial height of the stone

$V_{o}=20ft/s$ is the initial velocity of the stone

$t=6s$ is the time at which we need to find the height

$g=32ft/s^{2}$ is the acceleration due to gravity

Having this clear, let's find $y$ from (1):

$y=925ft+(20ft/s)(6s)-\frac{1}{2}(32ft/s^{2})(6s)^{2}$ (2)

Finally:

$y=469ft$ This is the height of the stone at t=6s

4 0

2 years ago

When someone asked you if you have a special talent.

Nostrana [21]

Answer:

lowkeyyyy

explanation:

4 0

2 years ago

Read 2 more answers

Five difference between elastic collision and inelastic collision?

olga_2 [115]

Answer:

Elastic Collision

Inelastic Collision

The total kinetic energy is conserved. The total kinetic energy of the bodies at the beginning and the end of the collision is different.

Momentum does not change. Momentum changes.

No conversion of energy takes place. Kinetic energy is changed into other energy such as sound or heat energy.

Highly unlikely in the real world as there is almost always a change in energy. This is the normal form of collision in the real world.

An example of this can be swinging balls or a spacecraft flying near a planet but not getting affected by its gravity in the end.

8 0

2 years ago