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abruzzese [7]
3 years ago
7

Earthquakes that originate beneath the ocean floor produce huge tidal waves called _____.

Physics
2 answers:
Vinvika [58]3 years ago
6 0

Answer:

tsunamis

Explanation:

ololo11 [35]3 years ago
3 0

Answer;

-Tsunami

Explanation;

-Tsunami  is a series of large ocean waves (or "wave train") of extremely long wavelength and period, usually generated when a gigantic body of water, such as an ocean, is suddenly displaced on a massive scale by an underwater disturbance such as an earthquake occurring on or near the sea floor or a volcanic eruption.

-After a sudden displacement of a large water volume by seismic activity (earthquake), the ocean floor is raised or dropped and large tsunami waves can be formed by gravitational forces.

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In a parallel circuit the component with the highest resistance will have a low electric current.
statuscvo [17]
Should be true.

it's been awhile since I was learning this
4 0
3 years ago
Please help on this one?
vlada-n [284]

Answer:

idk

Explanation:

7 0
3 years ago
The cart travels the track again and now experiences a constant tangential acceleration from point A to point C. The speeds of t
Veronika [31]

Answer:

the cart's speed at point B is 15.72 ft/s

Explanation:

 Given the data in the question;

The car travels from point A to C in 3.00 s, its average acceleration a_{avg} will be;

a_{avg}  = [V_{c}  - V_{A}] / Δt

V_{c} is 17.4 ft/s,   V_{A} is 13.2 ft/s and Δt is 3.00 s

so we substitute

a_{avg}  = [17.4 - 13.2] / 3

a_{avg}  = 4.2 / 3

a_{avg}  =  1.4 ft/s²

so average acceleration of the cart between the points  A and B is 1.4 ft/s²

The instantaneous value of the velocity of the cart at point B will be;

a_{avg}  = Δv / Δt

now substitute [V_{c}  - V_{B}] for Δv and t' for Δt

a_{avg}  = [V_{c}  - V_{B}] / t'

V_{B} = V_{c} - a_{avg}( t' )

so we substitute 17.4 ft/s for V_{c}, 1.20 s for t' and  a_{avg}  =  1.4 ft/s²

V_{B} = 17.4 - (1.4 × 1.20)

V_{B} = 17.4 - 1.68

V_{B} = 15.72 ft/s

Therefore, the cart's speed at point B is 15.72 ft/s

5 0
3 years ago
If you wanna make it easier you can number them going down 1,2,3, or 4 & just tell me the number
prisoha [69]

the number is 1 I hope this help

8 0
3 years ago
PLS HELP! What is the gravitational field strength on the moon?
astra-53 [7]

The gravitational field strength on the moon is \frac{1}{6} of the gravitational field strength on the earth

<u>On the earth:</u>

the gravitational field strength (g) is determined as:

g=G\frac{m}{r^2}

where:

  • G: the gravitational constant
  • m: the mass of the earth
  • r: the radius of the earth

g=9.8 N/kg = 9.8 m/s^2

<u>Then on the moon:</u>

g=[tex]\frac{1}{6}*9.8=1.6 N/kg[/tex]

<u>The answer will be</u> : A.1.6 N/kg

<u />

5 0
4 years ago
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