Answer: Le Chatleir Principle
Explanation: The answer of this question can be easily explanied through the Le Chatleir Principle which states that In order to maintain the equilibrium of the reaction, the stress applied to that particular direction will move the equilibrium to the opposite direction in which the stress has been applied.
The given reaction is -
If the amount of the oxygen is reduced to half and is being doubled, then the reaction will move in froward direction that is a rightward shift. Same situation will arise in option c and d.
If the amount of nitrogen monoxide is reduced to half or being doubled, the reaction will move towards backward direction that is a leftward reaction.
Answer:
Actually graphene is not occurred in naturally.
Explanation:
graphene is a layer or a sheet which is extracted from graphite because graphite is layered material. most of the time famous scotch tape may produce graphene but you can't identify it without using electron microscope
a. We first calculate the moles of sucrose needed
moles sucrose = 0.250 M * 0.25 L
moles sucrose = 0.0625 mol
The molar mass of sucrose 342.3 g/mol, so the mass of
sucrose needed is:
mass sucrose = 0.0625 mol * 342.3 g/mol
mass sucrose = 21.4 grams
So simply dissolved about 21.4 grams of sucrose in 250 mL
solution.
b. We use the formula:
M1 V1 = M2 V2
1.50 M * V1 = 0.100 M * 0.350 L
V1 = 0.0233 L = 23.3 mL
So simply take 23.3 mL of solution from 1.50 M then dilute
it with water until 350 mL to make 0.100 M.
Answer:
http://hyperphysics.phy-astr.gsu.edu/hbase/Biology/imgbio/treecycle.p ng
Explanation:
Answer:
pCl⁻ = 0.54
Explanation:
First we <u>calculate how many Cl⁻ moles are coming from each substance</u>, using the <em>given volumes and concentrations</em>:
- 0.12 M NaCl * 0.10 L = 0.012 mol NaCl = 0.012 mol Cl⁻
- 0.18 M MgCl₂ * 0.23 L = 0.0414 mol MgCl₂ = (0.0414 * 2) 0.0828 mol Cl⁻
The final volume of the mixture is = 0.10 L + 0.23 L = 0.33 L
Now we <u>calculate [Cl⁻]</u>, using the<em> total number of Cl⁻ moles and the final volume:</em>
- [Cl⁻] = (0.012 mol + 0.0828 mol) / 0.33 L = 0.29 M
Finally we <u>calculate the pCl⁻ of the resulting solution</u>:
